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3 years ago

PLS HELP I'LL GIVE THE BRAINLEST

Mathematics

2 answers:

Nata [24]3 years ago

7 0

Answer:

top right

Step-by-step explanation:

sorry if wrong

Alecsey [184]3 years ago

4 0

Answer: The graph on bottom right

Step-by-step explanation:

It’s the only one that correctly depicts the time (6 hours) and distance (300 miles) traveled. Starting at zero miles and zero drive time, it’s the only one that goes through 300 miles over a period of 6 hours.

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Please help me. I am pretty confused on this

Tanya [424]

Answer:

Step-by-step explanation:

16's square root is 4

8 0

3 years ago

Read 2 more answers

Please help me,ASAP

pav-90 [236]

Answer:

b. They can both be 90 degree angles

c. Acute angles are by definition 90 degrees, and acute is less than but not equal to 90 degrees

d. should be always

e. should be never (explanation: they have to be adjacent to be supplementary, and vertical angles are never adjacent)

Step-by-step explanation:

8 0

4 years ago

A/ab-bsquare + b/ab-asquare?

lord [1]

Answer:

$\dfrac{(a+b)}{ab}$

Step-by-step explanation:

The given expression is :

$\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}$

It can be solved as follows :

$\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}=\dfrac{a}{b(a-b)}+\dfrac{b}{a(b-a)}\\\\=\dfrac{a}{b(a-b)}+\dfrac{b}{-a(-b+a)}\\\\=\dfrac{1}{a-b}(\dfrac{a}{b}-\dfrac{b}{a})\\\\=\dfrac{a^2-b^2}{ab(a-b)}\\\\=\dfrac{(a-b)(a+b)}{ab(a-b)}\\\\=\dfrac{(a+b)}{ab}$

So, the solution of the given expression is equal to $\dfrac{(a+b)}{ab}$ .

7 0

3 years ago

PLEASE HELP

natima [27]

Answer:

x= 5/8

Step-by-step explanation:

7 0

2 years ago

ZE is the angle bisector of measure YEX and the perpendicular bisector of GF, GX is the angle bisector of measure YGZ and the pe

den301095 [7]

Answer:

Step-by-step explanation:

The center of inscribed circle into triangle is point of intersection of all interior angles of triangle.

The center of circumscribed circle over triabgle is point of intersection of perpendicular bisectors to the sides.

Circumscribed circle always passes through the vertices of the triangle.

Inscribed circle is always tangent to the triangle's sides.

In your case angles' bisectors and perpendicular bisectors intesect at one point, so point A is the center of inscribed circle and the center of corcumsribed circle. Thus, these circles pass through the points X, Y, Z and G, E, F, respectively.

7 0

3 years ago