The greatest outputs will be by function h.
Hope this helps.
Getting black is 1/4 of the percentage, and spinning it 10 times gives us 10/40, because there are 40 possible colors to land on when u spin it 10 times. The last spin, is just like any other time you spin it. just because it's the last spin, doesn't make the black sector greater. So the answer is 1/4 or 25%.
The answer would be 10 because the full side is 20 and it’s only asking for half the side so it would be 10
Answer:
We accept H₀. We do not have argument to keep the claim that the mean breaking strength has increased
Step-by-step explanation:
Normal Distribution
Population Mean μ₀ = 1850 pounds
Standard Deviation σ = 90 pounds
Type of test
Null Hypothesis H₀ ⇒ μ = μ₀
Alternative Hypothesis Hₐ ⇒ μ > μ₀
A one tail test (right)
n = 21 as n < 30 we use t-student table
degree of fredom 20
t = 2.845
Sample mean μ = 1893
Then, we compute t statistics
t(s) = [ 1893 - 1850 ] / 90/ √n
t(s) = 43 * 4,583 / 90
t(s) = 197,069 / 90
t(s) = 2,190
And we compare t and t(s)
t(s) = 2.190
t = 2.845
Then t(s) < t
We are in the acceptance zone, we accept H₀
