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Alisiya [41]
2 years ago
7

Mary wants to buy candies with an amount of money she has in her pocket.  we know that if she had $3.20 more money she could bu

y 120 candies. While if she had $2.40 less money she could buy 85 candies. What is the price per candy?
Mathematics
1 answer:
liubo4ka [24]2 years ago
5 0

Answer:

the price per candy is $0.16

and she has $16.00 in her pocket.

Step-by-step explanation:

x = the money in her pocket.

y = the price per candy

x + 3.2 = 120×y

x - 2.4 = 85×y

y = (x - 2.4)/85

=>

x + 3.2 = 120×(x - 2.4)/85 = (24x - 57.6)/17

=>

(17x + 17×3.2)/17 = (24x - 57.6)/17

17x + 54.4 = 24x - 57.6

54.4 = 7x - 57.6

112 = 7x

x = 16

y = (16 - 2.4)/85 = 13.6/85 = 0.16

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2 years ago
Manuel deposited $150 in his savings account on january 1. on the first day of each following month, he deposited an additional
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Answer:

8 months

Step-by-step explanation:

Subtract $150 from $430 to get $280, the amount if money that Manuel has to earn to reach his goal.

If he is adding $35 to his account each month, then all you have to do is divide the amount you need by the amount you are earning each month to get the number of months until you reach your goal.

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5 0
2 years ago
In a recent study on world​ happiness, participants were asked to evaluate their current lives on a scale from 0 to​ 10, where 0
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Answer:

a) A response of 8.9 represents the 92nd ​percentile.

b) A response of 6.6 represents the 62nd ​percentile.

c) A response of 4.4 represents the first ​quartile.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5.9

Standard Deviation, σ = 2.2

We assume that the distribution of response is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) We have to find the value of x such that the probability is 0.92

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.92

Calculation the value from standard normal z table, we have,  

P(z

\displaystyle\frac{x - 5.9}{2.2} = 1.405\\x = 8.991 \approx 8.9

A response of 8.9 represents the 92nd ​percentile.

b) We have to find the value of x such that the probability is 0.62

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.62

Calculation the value from standard normal z table, we have,  

P(z

\displaystyle\frac{x - 5.9}{2.2} = 0.305\\x = 6.571 \approx 6.6

A response of 6.6 represents the 62nd ​percentile.

c) We have to find the value of x such that the probability is 0.25

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.25

Calculation the value from standard normal z table, we have,  

P(z

\displaystyle\frac{x - 5.9}{2.2} = -0.674\\x = 4.4172 \approx 4.4

A response of 4.4 represents the first ​quartile.

4 0
3 years ago
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