Given a coordinate point (x, y), the first value of the point represents the value on the x-axis while the second value represent the value on the y-axis.
1.) To express the values (-4, -1), (-1, 2), (1, -4), (2, -3), (4, 3) as a table, we have:
x y -4 -1 -1 2 1 -4 2 -3 4 3
The values (-4, -1), (-1, 2), (1, -4), (2, -3), (4, 3) expressed as a graph have been attached as graph_1
To express the values (-4, -1), (-1, 2), (1, -4), (2, -3), (4, 3) as a mapping, we have two circles with one labelled x and the other one labelled y. Inside the circle labelled x are the numbers -4, -1, 1, 2, 4 written vertically and inside the circle labelled y are the numbers -4, -3, -1, 2, 3 written vertically. There are lines joining from the circle labelled x to the circle labelled y with line joining -4 in circle x to -1 in circle y, -1 in circle x to 2 in circle y, 1 in circle x to -4 in circle y, 2 in circle x to -3 in circle y, 4 in circle x to 3 in circle y.
The domain of the relation is the set of the x-values of the relation, i.e. domain is {-4, -1, 1, 2, 4}. The range of the relation is the set of the y-values of the relation, i.e. range is {-4, -3, -1, 2, 3}
2.) To express the values (-2, 1), (-1, 0), (1, 2), (2, -4), (4, 3) as a table, we have:
x y -2 1 -1 0 1 2 2 -4 4 3
The values (-2, 1), (-1, 0), (1, 2), (2, -4), (4, 3) expressed as a graph have been attached as graph_2
To express the values (-2, 1), (-1, 0), (1, 2), (2, -4), (4, 3) as a mapping, we have two circles with one labelled x and the other one labelled y. Inside
the circle labelled x are the numbers -2, -1, 1, 2, 4 written
vertically and inside the circle labelled y are the numbers -4, 0, 1, 2, 3 written vertically. There are lines joining from the circle labelled x to the circle labelled y with a line joining -2 in circle x to 1 in circle y, -1 in circle x to 0 in circle y, 1 in circle x to 2 in circle y, 2 in circle x to -4 in circle y, 4 in circle x to 3 in circle y.
The domain of the relation is the set of the x-values of the relation, i.e. domain is {-2, -1, 1, 2, 4}. The range of the relation is the set of the y-values of the relation, i.e. range is {-4, 0, 1, 2, 3}
The solution for this question is simple. First we need to divide both numbers by 2 which will give us 10 and 7. This is the equation x^2/10^2 + y^2/7^2 = 1sqrt(100-49) = 7.14 (the answer do not have a perfect square root) Foci are 14.28 units apart
You use the equation Final Velocity²= (Initial Velocity)² 2(Acceleration)(Distance). You plug in what you have 0²=22.4² X 2(-3.5)(D) and solve for D which is 71.68m or about 72m.