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3 years ago

10

Samantha buys a pair of sneakers that were originally $60. They were on sale for 25%

1 answer:

Alex_Xolod [135]3 years ago

3 0

Answer:

$47.70

Step-by-step explanation:

60.00 x .25 = 15 ( so $15.00 off the shoes )

60.00-15.00 = 45.00

45.00 x .06 = 2.70 (2.70 is your sales tax so add that to you sale price )

$45.00 + $2.70 =$47.70 Total

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Answer: 13. -68

14. 36

15. -36

16. -3

17. 10

18. -4

19. 1310 ft

20. 330 ft

Step-by-step explanation:

13. 34*(-2)=-68

14. -9*(-4)=

-(9*(-4))=

-(-36)=36

15. 12*(-3)=-36

16. -12/4=-3

17. -20/(-2)=

20/2=10

18. 200/(-50)=-4

19. -1640*(-1)-(-330*(-1))=

1640-(-330*(-1))=

1640-330=1310 ft

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1 year ago

Mrs.Alvarez bought a new car her monthly payments are $525.If she will pay a total of $25,200 in payments,write and solve a mult

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2 years ago

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Step-by-step explanation:

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2 years ago

Generate the nest three terms of each arithmetic sequence shown below.

o-na [289]

Answer:

A)2,6,10

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Step-by-step explanation:

<u>A)a1=-2 and d=4</u>

We know that the arithmetic sequence formula is

$a_{n}=a_{1}+(n-1)d$

Now

$a_{2}=a_{1}+(2-1)d$

$a_{2}=a_{1}+(1)d$

Substituting the given value we get

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$a_{2}= -2+4$

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------------------------------------------

Similarly

$a_{3}=a_{1}+(3-1)d$

$a_{3}=a_{1}+(2)d$

Substituting the given value we get

$a_{3}= -2+(2)4$

$a_{3}= -2+8$

$a_{3}= 6$

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$a_{4}=a_{1}+(4-1)d$

$a_{4}=a_{1}+(3)d$

Substituting the given value we get

$a_{4}= -2+(3)4$

$a_{4}= -2+16$

$a_{4}= 10$

-------------------------------------------------------------------------------------------

<u>B</u><u> $a_n=a_{(n-1)}-8$ with $a_1=10$ </u>

$a_2=a_{(2-1)}-8$

$a_2=a_{1}-8$

Substituting the given value

$a_2= 10-8$

$a_2=2$

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$a_3=a_{2}-8$

Substituting the value

$a_3=2-8$

$a_3= -6$

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$a_4=a_{(4-1)}-8$

$a_4=a_{3}-8$

Substituting the value

$a_4= -6-8$

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Here the difference is -2

the arithmetic sequence formula is

$a_{n}=a_{1}+(n-1)d$

Now

$a_{3}=a_{1}+(3-1)d$

$a_{3}=a_{1}+(2)d$

Substituting the value we get

$a_{3}= 3+(2)-2$

$a_{3}= 3-4$

$a_{3}= -1$

------------------------------------------------------------------------------

$a_{4}=a_{1}+(4-1)d$

$a_{4}=a_{1}+(3)d$

Substituting the value we get

$a_{4}= 3+(3)-2$

$a_{4}= 3-6$

$a_{4}= -3$

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$a_{5}=a_{1}+(4)d$

Substituting the value we get

$a_{5}= 3+(4)-2$

$a_{5}= 3-8$

$a_{5}= -5$

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