The final exam grade distribution for all students in the introductory statistics class at a local community college is displaye
d in the table, with A = 4, B = 3, C = 2, D = 1, and F = 0. Let X represent the grade for a randomly selected student from the class.
What is the standard deviation of the distribution?
A) 1.16
B) 1.08
C) 1.41
D) 2.98
What is the standard deviation of the distribution?
A) 1.16
B) 1.08
C) 1.41
D) 2.98
2 answers:
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Answer:
The probability that the cost for someone's dog is higher than for the cat is 33.2%.
Step-by-step explanation:
With the data given, we know that the difference in cost of medical care of dogs and cats have a normal distribution with μ=-20 and σ=46.
To know the probability of the cost for the dog is higher than the cat, we have to calculate the probability of P(d>0).
Then we have to calculate z, and look up in a standarized normal distribution table.
Calculate z:
The probability of the difference being higher than 0, we have:
We can say that the probability that the cost for someone's dog is higher than for the cat is 33.2%.