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marshall27 [118]
3 years ago
8

Answer these plssssssssssssssssssssss

Mathematics
1 answer:
lisov135 [29]3 years ago
8 0

Answer:

15: Yes, no, yes, yes, no; 16A: C = ($0.29)X + ($1.45)Y + ($2.50)Z; 16B: Yes

Step-by-step explanation:

For question 15: We need to multiply the widths and lengths given to see if they equal the area we are trying to achieve. Therefore, some of them work, and some do not.

For question 16:

Part A: We'll set a variable for the number of each supply she can buy. Pencils will be represented by X, pens by Y and Notebooks by Z, and we'll represent total cost by C. The total cost will therefore be represented by C = ($0.29)X + ($1.45)Y + ($2.50)Z.

Part B: We'll plug the numbers of items she wants to buy into our formula and see if it comes out to less than $20. So in this case C = ($0.29)(3) + ($1.45)(4) + ($2.50)(2). Therefore, C = $11.67, which is less than $20, so she can afford her school supplies.

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3 years ago
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kirill115 [55]

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The triangles are similar, so their sides are in ratio:

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6 0
3 years ago
Please help<br><br>numbers 42, 43, 44
Aleks [24]
<h3>Answer:</h3>

42.  29°

43.  3x³ +2x² -3x +10

44.  20a² +68a

<h3>Step-by-step explanation:</h3>

42.  The right-angle corner tells you the two marked angles are complementary — they sum to 90°.

  (-3x +20)° + (-2x +55)° = 90°

  -5x +75 = 90 . . . . . . . . . . collect terms, divide by °

  -5x = 15 . . . . . . . . . . . . . . . subtract 75

  x = -3 . . . . . divide by the coefficient of x

The angle of interest is (-3x+20)°. Filling in the found value for x, we have ...

  (-3·(-3) +20)° = 29° = m∠BDC

___

43.  The distributive property is useful for multiplying polynomials.

  (x +2)(3x² -4x +5) = x(3x² -4x +5) +2(3x² -4x +5)

  = 3x³ -4x² +5x +6x² -8x +10 . . . . . eliminate parentheses

  = 3x³ +2x² -3x +10

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44.  Area is the product of length and width, so this becomes a problem in multiplying polynomials.

  area = (5a +17)(4a) = 20a² +68a . . . . area in square feet

3 0
3 years ago
Three circles with centers A, B, and C are externally tangent to each other as shown in the figure. Lines EG and DG are tangent
fiasKO [112]
My solution to the problem is as follows:

EC = 15 ... draw CF = 6 (radius) ...use Pythagorean theorem to find EF. 

EF^2 + CF^2 = EC^2 
EF^2 = 15^2 - 6^2 = 189 .... EF = sq root 189 

triangle GDE is similar to CFE ... thus proportional 
GD / ED = CF / EF 
GD / 18 = 6 / (sq root 189) 
<span>GD = 108 / (sq root 189)

I hope my answer has come to your help. God bless and have a nice day ahead!


</span>
5 0
3 years ago
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