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krek1111 [17]
3 years ago
13

You put one ice cube on a room temperature rock and another ice cube on a room temperature piece of foil. Which ice cube will me

lt faster? Why?
Chemistry
1 answer:
aksik [14]3 years ago
5 0

Answer:

a ice cube on a room temperature rock

Explanation:

because the air temperature is warmer than the freezers which means the ice particle gather heat energy from warmer air.

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Sulfur is a nonmetalic mineral that has a density of 2 g/cm3. The volume of a sample of sulfur was measured to be 5.0 cm3. what
taurus [48]

Answer:

<h2>10 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 2 × 5

We have the final answer as

<h3>10 g</h3>

Hope this helps you

8 0
3 years ago
As the number of protons and neutrons in the nucleus increases, elements are much less likely to form stable, non-radioactive is
Murrr4er [49]
<span>The answer is iron. Iron has an atomic number of 26. This means than iron has 26 protons in it's nucleus. However, not all iron atoms have the same number of neutrons. Most commonly iron has 30 neutrons, but it also has 3 other stable isotopes. The word stable is important here because unstable elements are radioactive.</span>
7 0
3 years ago
Question 2(Multiple Choice Worth 2 points)
insens350 [35]

Answer:

location on the periodic table

Explanation:

6 0
3 years ago
What are the uses of an enema? Select all that apply. what are the uses of an enema? select all that apply. ?
shutvik [7]

An enema administration is a technique used to stimulate stool evacuation The process helps push waste out of the rectum when you cannot do so on your own

7 0
3 years ago
A laboratory experiment requires 4.8 l of a 2.5 m solution of sulfuric acid (h2so4), but the only available h2so4 is a 6.0 m sto
Airida [17]
To determine the amount of 6.0 M H2SO4 needed for the preparation, equate the number of moles of the 6.0 M and 2.5 M H2SO4 solution. This is done as follows
 
                                             M1 x V1 = M2 x V2

Substituting the known variables,
 
                                             (6.0 M) x V1 = (2.5 M) x (4.8 L)

Solving for V1 gives an answer of V1 = 2 L. Thus, to prepare the needed solution, dilute 2 L of 6.0 M H2SO4 solution with water until the volume reach 4.8 L. 


5 0
4 years ago
Read 2 more answers
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