2 years ago

Which of the following is a strong acid?

Chemistry

1 answer:

Leokris [45]2 years ago

3 0

Answer:

A) HCI( hydrochloric acid)

Explanation:

HCI is a strong acid because it has more number of hydrogen ions whereas acetic acid contains less number of hydrogen ions so its a weak acid

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How could you determine whether one of these two suspected compounds was identical to the unknown compound without using any for

sukhopar [10]

Answer: Use Mixture Melting Point

Explanation:

A procedure called mixture melting point would be used to determine whether or not the suspected compound is identical to the unknown.

The two suspected compounds would need to be used to create a new mixture and determine the mixtures melting point. Compare this melting points with that of the unknown compound in order to determine which one of these two suspected compounds is identical to the unknown compound.

4 0

2 years ago

A ball is dropped from a height of 1.20 m and hits the floor. The ball compresses and then reforms to spring upwards from the fl

diamong [38]

Answer:

$\large \boxed{\text{98 m$\cdot$s}^{-2}}$

Explanation:

The formula for the velocity of the ball is

$v = \sqrt{2gh}$

1. Velocity at time of impact

$v = -\sqrt{2 \times 9.807 \times 1.20} = -\sqrt{23.54} = -\textbf{4.85 m/s}$

2. Velocity on rebound

The ball has enough upward velocity to reach a height of 0.86 m.

$v = \sqrt{2 \times 9.807 \times 0.86} = \sqrt{16.87} =\textbf{4.11 m/s}$

3. Acceleration

$a = \dfrac{\Delta v}{\Delta t} = \dfrac{4.11 - (-4.85)}{ 0.091} = \dfrac{8.96 }{0.091} =\textbf{98 m$\cdot$s}^{\mathbf{-2}}\\\\\text{The acceleration while the ball is in contact with the floor is $\large \boxed{\textbf{98 m$\cdot$s}^{\mathbf{-2}}}$}$