To get the maximum height, we first determine the time at which this maximum height is attained by differentiating the given equation and equating the differential to zero.
h(t) = -0.2t² + 2t
Differentiating,
dh(t) = -(0.2)(2)t + 2 = 0
The value of t is equal to 5. Substituting this time to the original equation,
h(t) = -0.2(5²) + 2(5) = 5 ft
Thus, the maximum height is 5 ft and since it will take 5 seconds for it to reach the maximum height, the total time for it to reach the ground is 10 seconds.
Answers: maximum height = 5 ft
time it will reach the ground = 10 s
Answer:
D. 6 feet.
Step-by-step explanation:
The third longest side of ABCD is 12 feet long and the third longest side of EFGH is 18 feet long.
As they are similar the corresponding sides are in the same ratio so
12/18 = x/9 where x is the 4th side of ABCD.
2/3 = x/9
3x = 18
x = 6 feet.
What’s the rest of the qurstion?
Write the correct equation. Direct variation problems are solved using the equation y = kx. When dealing with word problems, you should consider using variables other than x and y, you should use variables that are relevant to the problem being solved. Also read the problem carefully to determine if there are any other changes in the direct variation equation, such as squares, cubes, or square roots.
Answer:
2(7x-4)
Step-by-step explanation:
