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GrogVix [38]
3 years ago
11

In a recent test, you scored 1.0 standard deviations above the average score attained, and the scores are normally distributed.

What percentage of students scored lower than you?
Mathematics
1 answer:
sesenic [268]3 years ago
3 0

Answer:

97.75 %

Step-by-step explanation:

You score 1 standard deviation above the mean

a) we have from left tail up to the mean 50 % of all values

b) We have in the interval  [ μ  -  σ  ;  μ  +  σ ] 95.5 % of all possible values, if we divide that 95.5 by 2 we get 47.75 %,  the part of the values that correspond to the right, then in order to get the  % of students scored lower we add

50  +  47.75   = 97.75 %

So you can say that the porcentage of students that scored lower than you is 97.75 %

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Answer:

Please check the explanation.

Step-by-step explanation:

To find the amount we use the formula:

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Given

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<em />

<u><em>Calculating compounded quarterly </em></u>

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A=2000\left(1+\frac{4.5\%\:}{4}\right)^{4\cdot \:5}

A=2000\left(1+\frac{0.045}{4}\right)^{4\cdot \:5}

A=2000\cdot \frac{4.045^{20}}{4^{20}}

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A = 2,501.50

Thus, If you deposit $2000 into an account paying 4.5% annual interest compounded quarterly, you will have $2501.50 after five years.

<u><em>Calculating compounded semi-annually</em></u>

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A=2000\left(1+\frac{0.045}{2}\right)^{2\cdot \:5}

A=2000\cdot \frac{2.045^{10}}{2^{10}}

A = 2,498.41

Thus, If you deposit $2000 into an account paying 4.5% annual interest compounded semi-annually, you will have $2,498.41  after five years.

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