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2 years ago

Can someone help me with this math homework please!

Mathematics

2 answers:

gladu [14]2 years ago

8 0

Answer:

As the x -values go to positive infinity, the functions values go to positive infinity.

Step-by-step explanation:

Korolek [52]2 years ago

4 0

Answer:

it is the second statement x⇒∞ Y⇒ ∞

Step-by-step explanation:

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Producing a musical costs $88,000 plus $5900 per performance. one sold out performance earns $7500 in revenue. If every performa

yan [13]

X = # of perfomances

y = total amount of money

Income: y = 7500x

Expense: y = 5900x + 88000

Substitution:

7500x = 5900x + 88000

1600x = 88000

x = 55

y = 7500(55) = $412,500

55 performances are needed to break-even.

5 0

3 years ago

Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2, 0)A(2,0)A

const2013 [10]

9514 1404 393

Answer:

28 square units

Step-by-step explanation:

The rectangle is 7-0 = 7 units high and 6-2 = 4 units wide. Its area is the product of these dimensions:

A = LW

A = (7)(4) = 28 . . . square units

3 0

2 years ago

Read 2 more answers

What is x+9=2(x_1)^2 in the form of ax^2+bx +c=0

Naddik [55]

<span>x + 9 = 2(x - 1)^2
x + 9 = 2(x^2 - 2x + 1)
x + 9 = 2x^2 - 4x + 2
</span>2x^2 - 4x + 2 - x - 9 = 0
2x^2 - 5x -7 =0

7 0

3 years ago

An item regularly priced at $49.95 was marked down to $44.95. Estimate the percent of discount

Zarrin [17]

Answer:

10%

Step-by-step explanation:

5 0

3 years ago

In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Liberal Arts Co

sukhopar [10]

Answer:

a. proportions have not changed significantly

Step-by-step explanation:

Given

Business College= 35 %

Arts College= 35 %

Education College = 30%

Calculated

Business College = 90/300= 9/30= 0.3 or 30%

Arts College= 120/300= 12/30= 2/5= 0.4 or 40%

Education College= 90/300= 9/30 = 0.3 or 30%

First we find the mean and variance of the three colleges using the formulas :

Mean = np

Standard Deviation= s= $\sqrt{npq\\}$

Business College

Mean = np =300*0.3= 90

Standard Deviation= s= $\sqrt{npq\\}$ = $\sqrt{0.3*0.7*300}$ = 7.94

Arts College

Mean = np =300*0.4= 120

Standard Deviation= s= $\sqrt{npq\\}$ = $\sqrt{0.4*0.6*300}$ = 8.49

Education College

Mean = np =300*0.3= 90

Standard Deviation= s= $\sqrt{npq\\}$ = $\sqrt{0.3*0.7*300}$ = 7.94

Now calculating the previous means with the same number of students

Business College

Mean = np =300*0.35= 105

Arts College

Mean = np =300*0.35= 105

Education College:

Mean = np =300*0.3= 90

Now formulate the null and alternative hypothesis

Business College

90≤ Mean≥105

Arts College

105 ≤ Mean≥ 120

Education College

U0 : mean= 90 U1: mean ≠ 90

From these we conclude that the proportions have not changed significantly meaning that it falls outside the critical region.

8 0

3 years ago