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Alexxandr [17]
2 years ago
12

Which of the following statements is true for the quadratic equation x2 – 16x + 64 = 0?

Mathematics
2 answers:
Art [367]2 years ago
7 0

Answer:

the equation has one anser

Step-by-step explanation:

irinina [24]2 years ago
6 0

Answer:

Please provide the statements.

Step-by-step explanation:

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CAN SOMEONE PLEASE HELP I NEED THESE LAST TWO I NEED TO TURN IT IN
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Answer: a. Area b. 4222.26

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3 years ago
-2(2n-2)>18-3n how do you solve this inequality
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-2 * 2n -2 equals -4n + 4 > 18n -3n

8 0
3 years ago
How do i do 3 part a ?
WINSTONCH [101]


In general the binomial expansion is


(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0


So in our case, because we want ascending powers of x we'll write,


(-3x + 1)^{11} =  {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9  + {11 \choose 3 } (-3x)^3 1^8 + ...


We need to calculate the binomial coefficients:


{11 \choose 0}  = 1


{11 \choose 1}  = 11


{11 \choose 2}  = \dfrac{11 \times 10}{2} = 55


{11 \choose 3}  = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165


(-3x+1)^{11} =  1 (-3x)^0 1^{11}  + 11(-3x)^{1} 1^{10}  + 55 (-3x)^2 1^{9}  + 165 (-3x)^3 1^8 + ...


(1-3x)^{11} =  1 -33 x + 495 3x^2 - 4455 x^3+ ...



6 0
3 years ago
Ruth works at a farmer's market and gets paid $50. she also gets paid $0.65 for each jar of jelly "j" she sells. which equation
34kurt

Answer:

Step-by-step explanation:

Ruth's salary is s(j), where s represents salary and j the number of jars she sells.

At the very beginning, she receives $50.  Only answer 'd' could be correct.

But also, the equation has the variable part 0.65j, or

$0.65j, which is directly proportional to the unit price of the jars of jelly.

*

Summing up the fixed and variable parts, we get

s = $50 + ($0.65j), or s = $50 + ($0.65/jar)j    This is Answer D.

7 0
2 years ago
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