What type of angles are 4 and 5

Help me please this is so hard

maxonik [38]

Answer: D. 136in^2

Step-by-step explanation:

Find the surface area if all sides and add

4*10=40

2*4=8

4*10=40

2*10=20

40+40+8+8+20+20=136

136in^2

3 0

3 years ago

I need help with that

weqwewe [10]

Distribute:

4x-3(x-2y)+1/2(6x-8y)

4x-3x+6y+3x-4y

Gather X and Y terms

x+6y+3x-4y

x+3x+6y-4y

Answer: 4x+2y

Hope I helped :)

6 0

3 years ago

Polygon CCC has an area of 404040 square units. K 2ennan drew a scaled version of Polygon CCC using a scale factor of \dfrac12 1

nikdorinn [45]

Answer:

Area of polygon D = 10 square units

Step-by-step explanation:

Given:

Polygon C has an area of 40 square units.

It is scaled with a scale factor of $\frac{1}2$ to form a new polygon D.

To find:

The area of polygon D = ?

Solution:

When any polygon is scaled to half, then all the sides of new polygon are half of the original polygon.

And the area becomes one-fourth of the original polygon.

Let us consider this by taking examples:

First of all, let us consider a right angled triangle with sides 6, 8 and 10 units.

Area of a right angled triangle is given by:

$A = \dfrac{1}{2} \times Base \times Height\\\Rightarrow A = \dfrac{1}{2} \times 6 \times 8 = 24\ sq\ units$

If scaled with a factor $\frac{1}{2}$ , the sides will be 3, 4 and 5.

New area, A':

$A' =\dfrac{1}{2} \times 3 \times 4 = 6\ sq\ units = \dfrac{1}4\times A$

i.e. Area becomes one fourth.

Let us consider a rectangle now.

Sides be 8 and 10 units.

Area of a rectangle, A = $Length \times Width$ = 8 $\times$ 10 = 80 sq units.

Now after scaling, the sides will be 4 and 5 units.

New Area, A' = 4 $\times$ 5 =20 sq units

So, $\bold{A' = \frac{1}4 \times A}$

Now, we can apply the same in the given question.

$\therefore$ Area of polygon D = $\bold{\frac{1}{4}}$ $\times$ Area of polygon C

Area of polygon D = $\bold{\frac{1}{4}}$ $\times$ 40 = 10 sq units

4 0

3 years ago

The pairs that equal to 4x-y=10

Tcecarenko [31]

You can work it out by using trial and error

so you get

x=3 , y=2

6 0

3 years ago

Resuelve las ecuaciones 3(2x-1)+5(x-3)=4x+7 5-x-(2x+3)= 3+8x

Ivan

Let's solve your equation step-by-step.3(2x−1)+5(x−3)=4x+7Step 1: Simplify both sides of the equation.3(2x−1)+5(x−3)=4x+7Simplify:11x−18=4x+7Step 2: Subtract 4x from both sides.11x−18−4x=4x+7−4x7x−18=7Step 3: Add 18 to both sides.7x−18+18=7+187x=25Step 4: Divide both sides by 7.7x7=257x=257Answer:x=257


Let's solve your equation step-by-step.5−x−(2x+3)=3+8xStep 1: Simplify both sides of the equation.5−x−(2x+3)=3+8xSimplify:−3x+2=8x+3Step 2: Subtract 8x from both sides.−3x+2−8x=8x+3−8x−11x+2=3Step 3: Subtract 2 from both sides.−11x+2−2=3−2−11x=1Step 4: Divide both sides by -11.−11x−11=1−11x=−111Answer:x=−111
Espero que esto ayude

4 0

3 years ago

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