Answer:
b - 9 = 2 I believe would be it
Answer:
Distance of JK = 15 unit
Step-by-step explanation:
Given:
J(4,8)
K(-1,-2)
Find:
Distance of JK
Computation:
Distance = √(x₂-x₁)² + (y₂-y₁)²
Distance of JK = √(-1-4)² + (-2-8)²
Distance of JK = √25 + 100
Distance of JK = √125
Distance of JK = 15 unit
Answer:
17
Step-by-step explanation:
a1=2a7 because the square route of (Tan) is 49 so it 2a7tan49 fa10 the answer is b
The person at the top is correct.