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anzhelika [568]
3 years ago
5

How to simplify (n+2)!/n! I will mark brainliest and give a thanks!

Mathematics
1 answer:
borishaifa [10]3 years ago
7 0
It would be (n+2) (n+1)
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Dafes stickball team has six players.how many different six player battling lineups can they make ifdave must bat second and eit
aalyn [17]
Let us name the players A,Dave,Zack,Paul,E and F 
For the first position there are two candidades ( Zack / Paul ) 
For the second position there is only one candidate i.e. Dave 
For the third place there will be 4 candidates (out of Zack and Paul - 1 as one of them is already taken for the first position and A, E and F total-4) 
For the fourth place there will be 3 candidates ( out of the four available candidates in the 3rd place, one will be taken up for 3rd place ) 
For the fifth place there will be 2 candidates 
Finally, for the last place there will be only one candidate left. 
On multiplying the no. of available cadidates, we get 2 * 1 * 4 * 3 * 2 * 1 = 48 i.e. option (A) 
Please mention minor spelling mistakes 
For the second question: 
Let the no of dotted marbles be 'x' and no of striped marbles be 'y' 
then the equation will become as follows 
(y+6)/x = 3 
and 
(x+6)/y = (2/3) 
On solving the equations, we will get x = 10 and y = 24 
Total balls = 10+24+6 = 40 (option E) 
Answer 3 will be ) For the first edge, he can choose 3 paths 
For the second edge he can choose 2 paths for each path of its first edge's path 
For the third , he is bounded to move on the paths created by the first and the second edges hence 1 path for each path created by the first and the second edge together 
It will be multiplication of all the possibilities of the paths of the three edges differently......... 
i.e. 3 * 2 * 1 = 6 
6 0
3 years ago
I really really really need help!!!!
Yakvenalex [24]
For f to be continuous at x=1, you need to have the limit from either side as x\to1 to be the same.

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^-}(|x-1|+2)=2
\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1^+}(ax^2+bx)=a+b

If a=2 and b=3, then the limit from the right would be 2+3=5\neq2, so the answer to part (1) is no, the function would not be continuous under those conditions.

This basically answers part (2). For the function to be continuous, you need to satisfy the relation a+b=2.

Part (c) is done similarly to part (1). This time, you need to limits from either side as x\to2 to match. You have

\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2^-}(ax^2+bx)=4a+2b
\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2^+}(5x-10)=0

So, a and b have to satisfy the relation 4a+2b=0, or 2a+b=0.

Part (4) is done by solving the system of equations above for a and b. I'll leave that to you, as well as part (5) since that's just drawing your findings.
8 0
2 years ago
4 / 500 in scientific notation would be?
Lubov Fominskaja [6]
4/500=0.008

scientific notation form = 8 x 10^9
3 0
3 years ago
-
RSB [31]

Answer:

Step-by-step explanation:

3x² - 3x + 7 = 0

a = 3 ; b = -3 and c = 7

D = b² - 4ac = (-3)² - 4*3*7

D = 9 - 84 = - 75

D = 75i²

√D = √75i² = \sqrt{5*5*3 * i * i}= 5i\sqrt{3}

x = \dfrac{-b+\sqrt{D}}{2a}  \ ; \  x=\dfrac{-b-\sqrt{D}}{2a}\\\\ \\x=\dfrac{3+5i\sqrt{3}}{6} ; \ ; x = \dfrac{3-5i\sqrt{3}}{6}\\\\\\x =\dfrac{3}{6}+\dfrac{5i\sqrt{3}}{6} ; \ ; x=\dfrac{3}{6}-\dfrac{5i\sqrt{3}}{6}\\\\\\Solution:\\\\x=\dfrac{1}{2}+\dfrac{5\sqrt{3}}{6}i ; \ ; x=\dfrac{1}{2}-\dfrac{5\sqrt{3}}{6}i

5 0
2 years ago
This past weekend Miss Thomas did some hallelujah shopping. She bought three presents and says that she has 30% of her shopping
Kaylis [27]

Answer: the number of presents that she has left to purchase is 6

Step-by-step explanation:

Let x represent the total number of presents that she has to purchase.

She bought three presents and says that she has 30% of her shopping finished. This means that she has finished (1/3 × x) = x/3 shopping. This is equivalent to 3 presents. Therefore,

x/3 = 3

x = 3×3 =9

She had 9 shopping to do

The number of shopping left will be total shopping that she has to do minus the shopping that she has done. It becomes

9 - 3 = 6

3 0
2 years ago
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