Answer:

Step-by-step explanation:
The formula for the length of a vector/line in your case.
![L = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{[4 - (-1)]^2 + [2 -(-3)]^2} = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}](https://tex.z-dn.net/?f=L%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%20%2B%20%28y_2-y_1%29%5E2%7D%20%3D%20%5Csqrt%7B%5B4%20-%20%28-1%29%5D%5E2%20%2B%20%5B2%20-%28-3%29%5D%5E2%7D%20%3D%20%5Csqrt%7B5%5E2%20%2B%205%5E2%7D%20%3D%20%5Csqrt%7B50%7D%20%3D%205%5Csqrt%7B2%7D)
Answer:
70° , 70°
Step-by-step explanation:
The 2 angles are corresponding and are congruent, then
23x + 1 = 4 + 22x ( subtract 22x from both sides )
x + 1 = 4 ( subtract 1 from both sides )
x = 3
Then the angles are
23x + 1 = 23(3) + 1 = 69 + 1 = 70°
4 + 22x = 4 + 22(3) = 4 + 66 = 70°
Answer: 130 ft
Step-by-step explanation:
a^2 + b^2 = c^2
Where a and b are the legs that form the right angle and c is the hypotenuse (the side directly opposite of the right angle)
50^2 + 120^2 = c ^2
2,500 + 14,400 = c^2
16,900 = c^2
Take the square root of 16,900 to get c.
C = 130
Hypotenuse length is 130
Answer:
x=106 degrees
Step-by-step explanation:
I'm going to assume that this is a circle since you didn't give it to me
So you want to add 164 and 90 together and subtract the sum by 360
360-(164+90)=106
So you want to use PEMDAS (order of operations) to solve this
- so do what's in the perenthesis first so 164+90=254
- Then you want to subtract 254 from 360 so 360-254=106
x=106 degrees