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pychu [463]
3 years ago
12

Which expression is equivalent to (4x^(3)y^(5))(3x^(5)y)^(2)

Mathematics
1 answer:
marshall27 [118]3 years ago
8 0

Answer:

(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7

Step-by-step explanation:

Given

(4x^3y^5)(3x^5y)^2

Required

The equivalent expression

We have:

(4x^3y^5)(3x^5y)^2

Expand

(4x^3y^5)(3x^5y)^2 = 4x^3y^5*9x^{10}y^2

Further expand

(4x^3y^5)(3x^5y)^2 = 4*9*x^3*x^{10}y^5*y^2

Apply laws of indices

(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7

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What force would be required to accelerate a 1,100 kg car to 0.5m/s?
ira [324]

Answer:

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Step-by-step explanation:

We can solve the problem by using Newton's second law:

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F is the force required to accelerate the car

m is the mass of the car

a is the acceleration of the car

In this problem, the mass is m=1100 kg, while the acceleration is a=0.5 m/s^2, therefore the force required to accelerate the car is

F=ma=(1100kg)(0.5m/s^{2} )=550N

Hope this helps!

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