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Stels [109]
3 years ago
7

Can someone please help me with these questions (picture)

Mathematics
2 answers:
Roman55 [17]3 years ago
5 0

Answer:

4 sqrt(5); 41.0

Step-by-step explanation:

Question 7:

Using Pythagoras theorem:

y = sqrt(12^2 - 8^2)

y = sqrt(80)

y = 4 sqrt(5)

Question 8:

A = Area rectangle + Area circle

A = 2.4 × 4.4 + pi × 4.4^2 ÷ 2

A = 10.56 + 9.68 pi

A = 41.0

Alexxx [7]3 years ago
4 0

Step-by-step explanation:

<em>Answer</em><em> </em><em>1</em><em> </em><em>to find the base</em><em> to apply the Pythagoras </em><em>theorem.</em><em>.</em><em>of</em><em> </em><em>finding</em><em> </em><em>length</em><em>.</em><em>.</em>

<em>Hypotenuse²</em><em>=</em><em> </em><em>Base²</em><em>+</em><em> </em><em>Height</em><em>²</em>

<em>So,</em>

<em>(</em><em>H</em><em>)</em><em>²</em><em>=</em><em> </em><em>(</em><em>B)</em><em>²</em><em>+</em><em>(</em><em>H)</em><em>²</em>

<em>1</em><em>2</em><em>²</em><em>=</em><em> </em><em>8</em><em>²</em><em>+</em><em>y²</em>

<em>1</em><em>4</em><em>4</em><em>-</em><em>6</em><em>4</em><em>=</em><em>y²</em>

<em>8</em><em>0</em><em>=</em><em>y²</em>

<em>√</em><em>8</em><em>0</em><em>=</em><em> </em><em>y</em>

<em>√</em><em>2</em><em>×</em><em>2</em><em>×</em><em>2</em><em>×</em><em>2</em><em>×</em><em>5</em><em>=</em><em> </em><em>y</em>

<em>2</em><em>×</em><em>2</em><em>√</em><em>5</em><em>=</em><em> </em><em>y</em><em> </em><em> </em><em>(</em><em> </em><em>take</em><em> </em><em>one</em><em> </em><em>2</em><em> </em><em>from</em><em> </em><em>each</em><em> </em><em>pair)</em>

<em>4</em><em>√</em><em>5</em><em>=</em><em> </em><em>y</em>

<em>hope</em><em> it</em><em> helps</em><em>.</em><em>.</em><em>.</em>

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