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3 years ago

Does 6.3 = 0.063 and which one is has more value.

2 answers:

5 0

Whenever you multiply number by another number smaller than 1 (but greater than 0), result will be smaller than original number.

For example: 1 × 0.99 = 0.99 (see, 0.99 is smaller than 1)

So multiplying 6.3 by 0.01 will be smaller than 6.3 itself.

So to answer your comment on your question, it's C.

wariber [46]3 years ago

3 0

They are not equal. 6.3 is greater

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Please help! And make sure to add a let statement!

Reptile [31]

Answer: See explanation

Step-by-step explanation:

1. Let the small number be x

Then, the bug number will be: x + 25

Therefore, x + x + 25 = 131

2x + 25 = 131

2x = 131 - 25

2x = 106

x = 106 / 2

x = 53

Small number= 53

Big number = x + 25 = 53 + 25 = 78

2. Let the small number be x

Then, the bug number will be: x + 14

x + x + 14 = 58

2x + 14 = 58

2x = 58 - 14

2x = 44

x = 44/2

x = 22

Small number = 22

Bug number = 22 + 14 = 36

The numbers are 22 and 36.

3. Let number of basketball sold be x

Therefore, number of football sold will be x+3.

Therefore, x + x + 3 = 27

2x + 3 = 27

2x = 27 - 3

2x = 24

x = 24/2

x = 12

12 basketball were sold

Number of footballs sold = 12 + 3 = 15

4. Let calories in bowl of soup x

Hamburger = 2 × x = 2x

Therefore, x + 2x = 738

3x = 738

x = 738/3

x = 246

There are 246 calories in bowl of soup

Calories in hamburgers = 246 × 2 = 492 calories

5 0

3 years ago

Could you help me plz

Nadya [2.5K]

Answer:

Step-by-step explanation:

(For a circle)

Circumference formula: π*2r

Area formula: π*r^2

π*2(3) =>6π=>18.84 m

π*(3)^2=>9π=>28.27 m^2

π*2(3.1)=>6.2π=>19.47 m

π*(3.1)^2=>9.61π=>30.19 m^2

6 0

3 years ago

What is the new price of s shirt that is on sale for 50% off and has an original price of $50?

satela [25.4K]

50%=1/2 or 1 half. 50/2=$25

5 0

4 years ago

Hiw ti factorise x*-16

ra1l [238]

Im assuming the problem is x^2-16, which would be factored to (x-4)(x+4)

7 0

3 years ago

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Jlenok [28]

Answer:

$x>2$

Step-by-step explanation:

When given the following inequality;

$(x^2+x-3):(x^2-4)\geq1$

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

$\frac{x^2+x-3}{x^2-4}\geq1$

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

$\frac{x^2+x-3}{x^2-4}-1\geq0$

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

$\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0$

Perform the operation on the other side distribute the negative sign and combine like terms;

$\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0$

Factor the equation so that one can find the intervales where the inequality is true;

$\frac{x+1}{(x-2)(x+2)}\geq0$

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

$-1, 2, -2$

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

$x\leq-2\\-2$

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

$x\leq-2$ -> negative

$-2$ -> neagtive

$-1\leq x$ -> neagtive

$x>2$ -> positive

Therefore, the solution to the inequality is the following;

$x>2$

6 0

3 years ago