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Georgia [21]
3 years ago
14

Please help me please please

Mathematics
1 answer:
LenKa [72]3 years ago
6 0

Answer:

1276.19553 m^{2}

Step-by-step explanation:

First, find height using Pythagoras thorem.

a=\sqrt{20^2+12.5^2}

a=15.61

Then use the formula to find the surface area of a cone.

π•12.5•(12.5+\sqrt{15.61^2+12.5^2})=1276.19553 m^{2}

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TEA [102]
251 is the smallest whole number

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3 years ago
-4x = -1/2(10x + 18)
frosja888 [35]

Answer:

x = -9

Step-by-step explanation:

-4x = -1/2(10x + 18)

Distribute

-4x= - 5x -9

Add 5x to each side

-4x+5x = -5x+5x -9

x = -9

5 0
3 years ago
Which expressions are equivalent to 35+30s-45t35+30s−45t35, plus, 30, s, minus, 45, t? Choose 2 answers:
laila [671]

Answer:

Options B

Options C

Options D

Step-by-step explanation:

35 + 30s - 45t

First term, 35

Factors:

= 1, 5, 7

Second term, 30s

Factors:

= 1, 2, 3 ,5

Third term, 45t

Factors:

= 1, 3, 3, 5

Common factors = 1, 5

5 × (7 + 6s - 9t)

10 × (3.5 + 3s - 4.5t)

-1 × (-35 - 30s + 45t)

8 0
3 years ago
Find the measure of angle B.
Elza [17]

Answer:

The measure of angle B is 122° ⇒ answer D

Step-by-step explanation:

* Lets explain how to solve the problem

- The sum of interior angles of any polygon can found by using this

  rule (n - 2) × 180° , where n is the number of the sides or angles

  of the polygon

∵ ABCDEFG is a polygon of 7 sides

∴ The sum of the measures of the interior angles = (7 - 2) × 180°

∴ The sum of the measures of the interior angles = 900°

∵ m∠A = 12x - 9 , m∠B = 9x + 14 , m∠C = 133° , m∠D = 10x + 9

∵ m∠E = 10x , m∠F = 136° , m∠G = 10x + 5

∵ The sum of all angles = 900°

∴ 12x - 9 + 9x + 14 + 133 + 10x + 9 + 10x + 136 + 10x + 5 = 900

∴ 51x + 288 = 900

- Subtract 288 from both sides

∴ 51x = 612

- Divide both sides by 51

∴ x = 12

∵ m∠B = 9x + 14

∵ x = 12

∴ m∠B = 9(12) + 14 = 122°

* The measure of angle B is 122°

3 0
3 years ago
Read 2 more answers
Use substitution to solve the system <br> 4x-5y=-35<br> y=<br> x=
timama [110]
Is really easy (
y
=
4
x
5
+
7
5 0
3 years ago
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