I'm not sure if this is what you're looking for, but maybe it will help:
Isolate y for 5=3x+2y
Switch sides:
3x+2y=5
Subtract 3x from both sides:
3x+2y-3x=5-3x
Simplify:
2y=5-3x
Divide both sides by 2:
2y/2 = 5-3x/2
Simplify:
y= 5x-3/2
I hope this helped you! :)
You need to find points where the line g(x) intercepts the quadratic function f(x) in one and only one point.
Then 3x^2 + 4x -2 = mx - 5
solve 3x^2 + 4x - mx -2 + 5 = 0
3x^2 + (4 - m)x + 3 = 0
In order to there be only one solution (one intersection point) the radicand of the quadratic formula must be 0 =>
b^2 - 4ac = (4 - m)^2 - 4(3)(3) = 0
(4 - m)^2 = 24
4 - m = +/- √(24)
m = 4 +/- √(24) = 4 +/- 2√(6)
Then m, the slope of the line, may be 4 + 2√6 and 4 - 2√6
Answer:
6. x + x + 14 = 90
2x + 14 = 90
2x = 76
x = 38
angle b = 38 + 14 = 52°
7. angles on a straight line add up to 180°
x + x - 32 = 180
2x = 212
x = 106°
angle d = 106 - 32 = 74°
8. vertically opposite angles are equal
7x - 80 = 3x
-80 = -4x
20 = x
angle 1 = 7(20) - 80 = 60°
angle 2 = 3(20) = 60°
Answer:
32.4kg
Step-by-step explanation:
if it loses one tenth of cement;
36kg×1/10
36kg/10
3.6kg was lost
to find the remaining ; 36kg - 3.6kg = 32.4kg is left in the bag
1. C. Rectangle
2. F. 160
3. D. Triangular prism
4. H. 30 boxes
5. C. Equilateral Triangle
