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bagirrra123 [75]
3 years ago
3

Select the correct answer. Based on the law of conservation of energy, which statement is correct? A. Energy is always being add

ed to all parts of the Universe. B. Energy is often destroyed in some parts of the Universe. C. Energy in a closed system cannot change forms. D. Energy in an isolated system remains constant.
Physics
1 answer:
NNADVOKAT [17]3 years ago
3 0

Answer:

D. Energy in an isolated system remains constant.

Explanation:

Energy can be defined as the ability (capacity) to do work. The two (2) main types of energy are;

a. Gravitational potential energy (GPE): it is an energy possessed by an object or body due to its position above the earth.

b. Kinetic energy (KE): it is an energy possessed by an object or body due to its motion.

Furthermore, the various forms of energy are solar energy, electrical energy, chemical energy, thermal energy, wind energy, nuclear energy etc.

The Law of Conservation of Energy states that energy cannot be destroyed but can only be transformed or converted from one form to another.

According to the law of conservation of energy, we can infer or deduce that the total energy of the system must stay the same because it cannot be destroyed, but kinetic energy (KE) can be transformed to potential energy (PE) and potential energy (PE) can be transformed to kinetic energy (KE) within the system.

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Which statement correctly describes the resistivity of a wire?
Karo-lina-s [1.5K]

Answer:

Resistivity depends on the material the wire is made from and has units of ohm-meters.

Explanation:

4 0
3 years ago
Fast breeder reactor technology definition
mixas84 [53]
The definition is a nuclear reactor that generates more fissile material than it consumes. 
5 0
3 years ago
Alguien me podria ayudar con esto pliz.. Ahora resuelva el siguiente ejercicio, tenga presente lo visto en clase y aprendido en
creativ13 [48]

Answer:

a.)1.)12m/s

2.)12m/s

3.)7m/s

4.)7m/s

5.)14m/s

6.)0m/s

b.)1.) 3m/s^2

2.)1.71m/s^2

3.).58m/s^2

4.).39m/s^2

5.).70m/s^2

6.)0

c.)1.)48m

2.)84m

3.)84m

4.)126m

5.)280m

6.)suma todos los metros mas 98m y obtendras la distancia en cual el carro se para

Explanation:

vinicial=0m/s

tiempo inicial=0s

Intervalo 1

v=12m/s

t=4s

aceleracion= vf-vi/t

=12-0/4

=12/4=3m/s^2

Intervalo 2

v=12m/s

t=7s

a=12/7

Intervalo 3

v=7m/s

t=12s

a=7/12

Intervalo 4

v=7m/s

t=18s

a=7/18

Intervalo 5

v=14m/s

t=20s

a=14/20

Intervalo 6

v=0m/s

t=27s

a=0/27

7 0
3 years ago
The diver on the diving board is 10 meters high and has a mass of 0.050kg, what is his GPE?
sveta [45]

Answer:

<h2>4.9 J</h2>

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

GPE = 10 × 9.8 × 0.05

We have the final answer as

<h3>4.9 J</h3>

Hope this helps you

6 0
3 years ago
A 31 kg block is initially at rest on a horizontal surface. A horizontal force of 83 N is required to set the block in motion. A
Hatshy [7]

Answer:

The static and kinetic coefficients of friction are 0.273 and 0.181, respectively.

Explanation:

By Newton's Laws of Motion and definition of maximum friction force, we derive the following two formulas for the static and kinetic coefficients of friction:

\mu_{s} = \frac{f_{s}}{m\cdot g} (1)

\mu_{k} = \frac{f_{k}}{m\cdot g} (2)

Where:

\mu_{s} - Static coefficient of friction, no unit.

\mu_{k} - Kinetic coefficient of friction, no unit.

f_{s} - Static friction force, in newtons.

f_{k} - Kinetic friction force, in newtons.

m - Mass, in kilograms.

g - Gravitational constant, in meters per square second.

If we know that f_{s} = 83\,N, f_{k} = 55\,N, m = 31\,kg and g = 9.807\,\frac{m}{s^{2}}, then the coefficients of friction are, respectively:

\mu_{s} = \frac{83\,N}{(31\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}

\mu_{s} = 0.273

\mu_{k} = \frac{55\,N}{(31\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}

\mu_{k} = 0.181

The static and kinetic coefficients of friction are 0.273 and 0.181, respectively.

4 0
3 years ago
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