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3 years ago

Help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee I am going to follow youuu

Physics

2 answers:

sveta [45]3 years ago

5 0

The ans is 11 and i’m sure darling dw

Y_Kistochka [10]3 years ago

3 0

Answer:

Answer 11

Explanation:

. Newton's law of gravitation, statement that any particle of matter in the universe attracts any other with a force varying directly as the product of the masses and inversely as the square of the distance between them

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Adding a catalyst to a reaction has an effect similar to

mariarad [96]

The answer to your question is B.

8 0

3 years ago

Two point charges, A and B, are separated by a distance of 19.0 cm . The magnitude of the charge on A is twice that of the charg

Hatshy [7]

Answer:

The charge on point A is $q_a$ = 2.4 × $10^{-5}$ C

The charge on point B is $q_b$ = 1.2 × $10^{-5}$ C

Explanation:

Given data

Distance (r) = 0.19 m

Magnitude of the charge on A is twice that of the charge on B i.e.

$q_A = 2 q_B$

F = 46 N

We know that force between the charges is given by

$F = \frac{k Q_A Q_B}{r^{2} }$

$65 = \frac{(9) (10^{9}) (2q_b^{2} ) )}{0.2^{2} }$

$q_b$ = 1.2 × $10^{-5}$ C

$q_a$ = 2 × $q_b$

$q_a$ = 2 × 1.2 × $10^{-5}$

$q_a$ = 2.4 × $10^{-5}$ C

Therefore the charge on point A is $q_a$ = 2.4 × $10^{-5}$ C

The charge on point B is $q_b$ = 1.2 × $10^{-5}$ C

6 0

4 years ago

A student throws a water balloon with speed v0 from a height h = 1.82 m at an angle θ = 29° above the horizontal toward a target

3241004551 [841]

Answer:

$v_o = 7.76 m/s$

Explanation:

As we projected the balloon at speed vo at an angle of 29 degree

so the two component of velocity is given as

$v_x = v_ocos29 = 0.875 v_o$

$v_y = v_o sin29 = 0.485 v_o$

now we know that in x direction we have

$d = v_x t$

$7.5 = 0.875 v_o t$

$v_o t = 8.57$

in y direction we have

$- 1.82 = (0.485 v_o) t - \frac{1}{2}gt^2$

$-1.82 = 0.485(8.57) - 4.9 t^2$

$t = 1.1 s$

now we have

$v_o = 7.76 m/s$

7 0

4 years ago

A particle moving in a straight line with a constant acceleration covers 10m in 2 seconds and 22m in a further 2 seconds. How mu

MrRissso [65]

The particle will travel a distance of 28 m in the next two seconds

<h3>Acceleration</h3>

Acceleration is defined as the change in velocity with time

Acceleration = final velocity - initial velocity / time

<h3>Calculating initial velocity</h3>

distance covered = 10 m

time = 2 seconds

velocity = distance/time

initial velocity = 10/2

initial velocity = 5m/s

<h3>Calculating final velocity</h3>

distance = 22 m

time = 2 seconds

Final velocity = 22/2

Final velocity = 11 m/s

<h3>Calculating acceleration</h3>

Acceleration = change in velocity/time

acceleration = 11m/s - 5m/s /2 s

acceleration = 3m/s²

<h3>Calculating distance covered</h3>

Using the equation of motion:

s = ut + at²/2

s = 11 * 2 + 3 * 2²/2

s -=28 m

Therefore, the particle will travel a distance of 28 m in the next two seconds

Learn more about distance and acceleration at: brainly.com/question/16847527

7 0

3 years ago

A car jack with a mechanical advantage of 8 needs to produce an output force of 400 N to raise a car. What input force is requir

allsm [11]

Answer:

533 n

Explanation:

6 0

3 years ago