2 years ago

PLZZ SEND HELP!!!!!!!!!! WILL GIVE YOU BRAINLIEST! Find

Mathematics

1 answer:

SOVA2 [1]2 years ago

6 0

Answer:

find what?

Step-by-step explanation:

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The expression 3xy-(2x+4xy) is equivalent to

Goryan [66]

There are no answer options so I will just simplify the expression:
3xy-(2x+4xy)
3xy-2x-4xy
-2x-xy

3 0

3 years ago

There is a decrease in power. It can be concluded that there has also been a change in: A)current or voltage.

Serhud [2]

There is a decrease in power. It can be concluded that there has also been a change in:

A) current or voltage.

5 0

3 years ago

3125x=−62 value of x.

Papessa [141]

Answer:

x= -0.01984

Step-by-step explanation:

You divide both sides by 3125 to get x alone.

You get x=-0.01984

Hope this helps!

5 0

2 years ago

If the probability of making a 3-point shot is 30%, how many made 3-pointers would you predict the player would make if they sho

Marianna [84]

Answer:

30 three-pointers

Step-by-step explanation:

if u need explanation, lmk and i'll type it in the comments to this question.

8 0

3 years ago

Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}

miskamm [114]

Answer:

$-3+i\sqrt{3} , 1+\sqrt{3}$

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

$\alpha = x+iy\\\beta = x-iy$

since they are conjugates

$\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}$

$\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}$

Imaginary part of the above =0

i.e. $\sqrt{3} (x^2-3)+2x\sqrt{3} =0\\x^2+2x-3=0\\(x+3)(x-1) =0\\x=-3,1$

So the value of alpha = $-3+i\sqrt{3} , 1+\sqrt{3}$

3 0

3 years ago