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Veronika [31]
2 years ago
14

Write an equation for the line that contains (6, 15) that is parallel to the line with equation x−2y=−10. Write your equation in

slope-intercept form. Show your work!
Mathematics
1 answer:
prisoha [69]2 years ago
6 0

Answer:

y=1/2+12

Step-by-step explanation:

first you have to find the slope to the first equation and that is x/2 and then you have to use the point and plug all of that into slope intercept form(y=mx+b)

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What is the answer of this question plzzzzzzzzzzz say fast​
Softa [21]

Answer:

1=3=70^{0} \\2=4=5=110^{0}

Step-by-step explanation:

Given angle is 110°

Now,

4=2\,\,and\,\,4=5\,\,;[vertical\,\,angle\,\,and\,\,corresponding\,\,angle\,\,respectively ]

From the figure,

4=110^{0}\,\,;[alternate\,\,angle]

So,\,\,2=5=110^{0}

And, as 1,2,3,4 are vertical angles and 2 = 4 = 110°

1 = 3 = 180° - 110° = 70°

Hope you have understood this.....      

ask me if you have any confusion.....      

if you liked it pls mark it as the brainliest

7 0
3 years ago
Read 2 more answers
Find inverse of f(x)=x^3-9<br>Not sure of my answer!​
Katyanochek1 [597]

as you may already know, to get the inverse of any expression, we start off by doing a quick switcheroo on the variables, and then solve for "y".

\bf \stackrel{f(x)}{y}=x^3-9\implies \stackrel{\textit{quick switcheroo}}{\underline{x}=\underline{y}^3-9}\implies x+9=y^3\implies \sqrt[3]{x+9}=\stackrel{f^{-1}(x)}{y}

7 0
3 years ago
What are some ways you can create a new system of equations based on a given system?
docker41 [41]
By adding/ subtraction systems
3 0
3 years ago
Please help with 18 and 19 ASAP ill do brainiac
DanielleElmas [232]

Answer:

18). y = -x

19). y = -2x + 4

3 0
3 years ago
A right cone has a surface area of 440 square inches and a radius of 7 inches. Find its slant height.
EastWind [94]

Answer:

Surface Area of right cone  

               =\pi r(r+\sqrt{h^2 + r^2}

440 = \pi *7*(7+\sqrt{h^2+7^2})\\\\440 = 7\pi (7 + \sqrt{h^2+7^2})\\\\\frac{440}{7\pi } = 7 + \sqrt{h^2+49}\\\\\frac{440}{7\pi } - 7 = \sqrt{h^2+49}\\\\\frac{440-49\pi}{7\pi} =\sqrt{h^2+49}\\\\

\frac{286.062}{21.99} =\sqrt{h^2+49}\\\\13.0087= \sqrt{h^2+49}\\\\(13.0087)^2 = (\sqrt{h^2+49})^2\\\\169.227 = h^2 +49\\\\169.227 - 49 =h^2\\\\120.227 = h^2\\\\h = \sqrt{120.227}  = 10.96in

7 0
2 years ago
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