Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
Answer:
Step-by-step explanation:
The area of a trapezium is given as;
Area = 
(a + b)h
where: a is the length of the upper side, b is the length of its base and h is its height.
This implies that; a = x - 4, b = x + 5, h = 2x and area = 351
Thus,
351 = ((x - 4) + (x + 50)) 2x
= (x - 4 + x + 5) x
531 = (2x + 1) x
= 2
+ x
So that;
2 + x - 531 = 0
This gives a quadratic equation.
Answer:
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Step-by-step explanation:
Answer:
0. toab1. The right answer for K12 is ( > ) I Took the test and is correct. 4×16-16 > 4× [24-2× (4+8)] heart outlined. Thanks 0. star outlined. star outlined. star outlined.
5^0 x 5^4 1 x 625 625
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5^3 x 5^1 125 x 5 625
