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3 years ago

X/18 = (2/3)^log base x of 12

Mathematics

1 answer:

nadya68 [22]3 years ago

4 0

Answer:

wait what is that what the question ask you to do

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The sum of x and 16 is less than 32

OleMash [197]

I'm unsure of the question but this expression can be written as:
16 + x < 32.
This can be simplified to:
x < 16

5 0

3 years ago

The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) 5x/x^2

Olegator [25]

Given :

The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by $K(x) = \dfrac{5x}{x^2+9}$ .

To Find :

Find the time at which the concentration is a maximum. b. Find the maximum concentration.

Solution :

For maximum value of x, K'(x) = 0.

$K'(x) = \dfrac{5(x^2+9)- 5x(2x)}{(x^2+9)^2}=0\\\\5x^2+45-10x^2=0\\\\5x^2 = 45\\\\x = \pm 3$

Since, time cannot be negative, so ignoring x = -3 .

Putting value of x = 3, we get, K(3) = 15/( 9 + 9) = 5/6

Therefore, maximum value drug in bloodstream is 5/6 at time x = 3 units.

Hence, this is the required solution.

5 0

2 years ago

Help really quick and fast plzzzzzz

mr Goodwill [35]

Answer:

Step-by-step explanation:

7 0

3 years ago

Rewrite this standard form quadratic equation into vertex form by completing the square. Upload your work here to show your thin

Alex787 [66]

Solution :

Given the equation :

$y = x^2 - 6x+3$

$y=1(x^2 - 6x +n)+3$

$n = \left(\frac{b}{2}\right)^2$

$n = \left(\frac{6}{2}\right)^2$

n = 9

$y=1(x^2 - 6x +9-9)+3$

$y=1(x^2 - 6x +9)-9+3$

$y=1(x-3)^2- 6$

Therefore the vertex form of $y = x^2 - 6x+3$ is $y=1(x-3)^2- 6$ .

3 0

2 years ago

Do the three points lie on one line?

padilas [110]

Answer:

Yes. No graph paper.

Step-by-step explanation:

Let's say the 3 points are A, B, C.

If A, B and C lie on one line then $m_{AB} = m_{BC} = m_{AC}$

$m_{AB} = \frac{y_{B}-y_{A} }{x_{B}-x_{A}} = \frac{2-6}{3-5} = \frac{-4}{-2} = 2\\m_{BC} = \frac{y_{C}-y_{B} }{x_{C}-x_{B}} = \frac{8-2}{6-3} = \frac{6}{3} = 2\\\\m_{AC} = \frac{y_{C}-y_{A} }{x_{C}-x_{A}} = \frac{8-6}{6-5} = \frac{2}{1} = 2\\\\$

Hence, they lie on one line.

You don't need to use a graph paper to prove it.

4 0

2 years ago