Question

Prove: smiddle" class="latex-formula"> = \frac{c}{d}[/tex], then$\frac{a+b}{b} = \frac{c+d}{d}$. show work pls :)

Answer 1

Step-by-step explanation:

$\dfrac{a}{b} = \dfrac{c}{d}$

Add 1 to both sides of the equation:

$\dfrac{a}{b} + 1 = \dfrac{c}{d} + 1$

Note that

$\dfrac{a}{b} + 1 = \dfrac{a + b}{b}$

Likewise,

$\dfrac{c}{d} + 1 = \dfrac{c + d}{d}$

Therefore,

$\dfrac{a + b}{b} = \dfrac{c + d}{d}$