Question

Please I need help with this!!!!!!!

Answer 1

Answer:

Step-by-step explanation:

1). Step 4:

   $x=5^{\frac{4}{3}}=(5^4)^{\frac{1}{3}}$

   $x=\sqrt[3]{5^4}$ [Since, $a^{\frac{1}{3}}=\sqrt[3]{a}$]

   $x=\sqrt[3]{5\times 5\times 5\times 5}$

   Step 5:

   $x=\sqrt[3]{(5)^3\times 5}$

   $x=\sqrt[3]{5^3}\times \sqrt[3]{5}$

2). He simplified the expression by removing exponents from the given expression.

3). Let the radical equation is,

   $(3x-1)^{\frac{1}{5}}=2$

   Step 1:

   $(3x-1)^{\frac{1}{5}\times \frac{5}{1} }=2^{\frac{5}{1}}$

   Step 2:

   $(3x-1)=2^5$

   Step 3:

   $3x=32+1$

   Step 4:

   $x=11$

4). By substituting $x=11$ in the original equation.

   $(3\times 11-1)^{\frac{1}{5}}=(32)^\frac{1}{5}$

                         $=(2^5)^\frac{1}{5}$

                         $=2$

There is no extraneous solution.