Answer: 2 lbs of cherries
Cherries = $5 per pound
Oranges = $2 per pound
Total Cost = $18
Total weight = 6 lb
------------------------------------
Define x and y
------------------------------------
Let x be the number of lb of cherries
Let y be the number of lb of oranges
------------------------------------
Construct equations
------------------------------------
x + y = 6 ---------------------------- (1)
5x + 2y = 18 ---------------------------- (2)
------------------------------------------------------------------------
Solve x and y
------------------------------------------------------------------------
From equation (1):
x + y = 6
x = 6 - y
------------------------------------------------------------------------
Substitute x = 6 - y into equation 2
------------------------------------------------------------------------
5x + 2y = 18
5 (6 - y) + 2y = 18
30 - 5y + 2y = 18
3y = 30 - 18
3y = 12
y = 4
------------------------------------------------------------------------
Substitute y = 4 into equation (1)
------------------------------------------------------------------------
x + y = 6
x + 4 = 6
x = 2
------------------------------------------------------------------------
Find the weight of cherries and oranges
------------------------------------------------------------------------
Cherry = x = 2 lb
Oranges = y = 4 lbs
------------------------------------------------------------------------
Answer: Alex bought 2 lb of cherries
------------------------------------------------------------------------
Answer:
15 minutes
35 minutes
20 minutes
Step-by-step explanation:
The first quartile is given by the starting point of the box on the plot, this point corresponds to 15 minutes
The maximum time is obtijed from the endpoint of the whisker, this corresponds to 35 minutes.
The median value corresponds to the vertical line in between the box on the plot, this point is designated as 20!minutes in the plot.
Answer:
The 9th term is 17179869184
Step-by-step explanation:
Here we have that;
The divisors of 1 = 1 which is 1 less than 1*2
The sum of the divisors of 2 = 1 + 2 = 3 which is 1 less than 2*2
The sum of the divisors of 4 = 1 + 2 + 4 which is 1 less than 4*2
The sum of the divisors of 8 = 1 + 2 + 4 + 8 which is 1 less than 8*2
The sum of the divisors of 32 = 1 + 2 + 4 + 8 + 16 + 32 which is 1 less than 32*2
The sum of the divisors of 256 = 1 + 2 + 4 + 8 + 16 + 32 + 64 + 128 + 256 which is 1 less than
The next numbers are therefore,
32 × 256 = 8192
256 × 8192 = 2097152 and the 9th term is therefore;
8192 × 2097152 = 17179869184.
Answer:
(a) 
(b)
Step-by-step explanation:
Let´s use Divided Differences Method of Polynomial Interpolation given by this iteration:
![f[x_k,x_k_+_1,...,x_k_+_i]=\frac{f[x_k_+_1,x_k_+_2,...,x_k_+_i]-f[x_k,x_k_+_1,...,x_k_+i_-_1]}{x_k_+_i-x_k}](https://tex.z-dn.net/?f=f%5Bx_k%2Cx_k_%2B_1%2C...%2Cx_k_%2B_i%5D%3D%5Cfrac%7Bf%5Bx_k_%2B_1%2Cx_k_%2B_2%2C...%2Cx_k_%2B_i%5D-f%5Bx_k%2Cx_k_%2B_1%2C...%2Cx_k_%2Bi_-_1%5D%7D%7Bx_k_%2B_i-x_k%7D)
k∈[0,n-i]
Thus the Newton polynomial can be written as:
![P_n_-_1(x)=f[x_0]+f[x_0,x_1](x-x_0)+f[x_o,x_1,x_2](x-x_0)(x-x_1)+...+f[x_n,x_n_-_1,...,x_1](x-x_n)(x-x_n_-_1)...(x-x_1)](https://tex.z-dn.net/?f=P_n_-_1%28x%29%3Df%5Bx_0%5D%2Bf%5Bx_0%2Cx_1%5D%28x-x_0%29%2Bf%5Bx_o%2Cx_1%2Cx_2%5D%28x-x_0%29%28x-x_1%29%2B...%2Bf%5Bx_n%2Cx_n_-_1%2C...%2Cx_1%5D%28x-x_n%29%28x-x_n_-_1%29...%28x-x_1%29)
(a) I attached you the procedure in the first table, using it we have:

Operate P(x) using the distributive property:

(b) I attached you the procedure in the second table, using it we have:

Operate P(x) using the distributive property:
