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3 years ago

Find the solution to the following system of equations using substitution or elimination

Mathematics

1 answer:

Serggg [28]3 years ago

7 0

Answer:

D. (2,-3)

Step-by-step explanation:

if you substitute 2 for the x value and -3 for the y value in both equations, it works out.

instead of y=3x-9 it would be -3=3(2)-9.

you solve and get -3=-3, so it's a solution.

and instead of y=-2x+1 it would be -3=2(2)+1. after solving it, you would get -3=-3 again, so it works for both equations.

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Can I get some help?

lapo4ka [179]

Answer:

The answer is reduction

4 0

3 years ago

Read 2 more answers

Cherries $5 per pound and oranges per pound$2. He paid 18.00 for total weight which was 6 lbs how many pounds of cherries did Al

wel

Answer: 2 lbs of cherries

Cherries = $5 per pound
Oranges = $2 per pound
Total Cost = $18
Total weight = 6 lb

------------------------------------
Define x and y
------------------------------------
Let x be the number of lb of cherries
Let y be the number of lb of oranges

------------------------------------
Construct equations
------------------------------------
x + y = 6 ---------------------------- (1)
5x + 2y = 18 ---------------------------- (2)

------------------------------------------------------------------------
Solve x and y
------------------------------------------------------------------------
From equation (1):
x + y = 6
x = 6 - y

------------------------------------------------------------------------
Substitute x = 6 - y into equation 2
------------------------------------------------------------------------
5x + 2y = 18
5 (6 - y) + 2y = 18
30 - 5y + 2y = 18
3y = 30 - 18
3y = 12
y = 4

------------------------------------------------------------------------
Substitute y = 4 into equation (1)
------------------------------------------------------------------------
x + y = 6
x + 4 = 6
x = 2

------------------------------------------------------------------------
Find the weight of cherries and oranges
------------------------------------------------------------------------
Cherry = x = 2 lb
Oranges = y = 4 lbs

------------------------------------------------------------------------
Answer: Alex bought 2 lb of cherries
------------------------------------------------------------------------

5 0

3 years ago

1) The incubation time (in days) of a canary, dove, mynah, pegion, parakeet, raven,

allochka39001 [22]

Answer:

15 minutes

35 minutes

20 minutes

Step-by-step explanation:

The first quartile is given by the starting point of the box on the plot, this point corresponds to 15 minutes

The maximum time is obtijed from the endpoint of the whisker, this corresponds to 35 minutes.

The median value corresponds to the vertical line in between the box on the plot, this point is designated as 20!minutes in the plot.

4 0

3 years ago

A series consists of some numbers such that the summation of the divisors of any number of that series is 1 less than twice of t

dezoksy [38]

Answer:

The 9th term is 17179869184

Step-by-step explanation:

Here we have that;

The divisors of 1 = 1 which is 1 less than 1*2

The sum of the divisors of 2 = 1 + 2 = 3 which is 1 less than 2*2

The sum of the divisors of 4 = 1 + 2 + 4 which is 1 less than 4*2

The sum of the divisors of 8 = 1 + 2 + 4 + 8 which is 1 less than 8*2

The sum of the divisors of 32 = 1 + 2 + 4 + 8 + 16 + 32 which is 1 less than 32*2

The sum of the divisors of 256 = 1 + 2 + 4 + 8 + 16 + 32 + 64 + 128 + 256 which is 1 less than

The next numbers are therefore,

32 × 256 = 8192

256 × 8192 = 2097152 and the 9th term is therefore;

8192 × 2097152 = 17179869184.

4 0

3 years ago

Consider the following points.

horrorfan [7]

Answer:

(a) $P(x)=0.4x^{3} +2x^{2} -1.4x$

(b) $P(x)=x^{4} -x^{3} +5x^{2} -7x-14$

Step-by-step explanation:

Let´s use Divided Differences Method of Polynomial Interpolation given by this iteration:

$f[x_k,x_k_+_1,...,x_k_+_i]=\frac{f[x_k_+_1,x_k_+_2,...,x_k_+_i]-f[x_k,x_k_+_1,...,x_k_+i_-_1]}{x_k_+_i-x_k}$

k∈[0,n-i]

Thus the Newton polynomial can be written as:

$P_n_-_1(x)=f[x_0]+f[x_0,x_1](x-x_0)+f[x_o,x_1,x_2](x-x_0)(x-x_1)+...+f[x_n,x_n_-_1,...,x_1](x-x_n)(x-x_n_-_1)...(x-x_1)$

(a) I attached you the procedure in the first table, using it we have:

$P(x)=3+(-3)(x+1)+(2)(x+1)(x)+0.4(x+1)(x)(x-1)$

Operate P(x) using the distributive property:

$P(x)=0.4x^{3} +2x^{2} -1.4x$

(b) I attached you the procedure in the second table, using it we have:

$P(x)=44+(-44)(x+2)+(15)(x+2)(x+1)+(-3)(x+2)(x+1)(x)+(1)(x+2)(x+1)(x)(x-1)$

Operate P(x) using the distributive property:

$P(x)=x^{4} -x^{3} +5x^{2} -7x-14$

6 0

3 years ago

Find the solution to the following system of equations using substitution or elimination​

Find the solution to the following system of equations using substitution or elimination