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svp [43]
3 years ago
13

What multiplication fact could help me find out 24 ÷ 8 ?

Mathematics
2 answers:
Semenov [28]3 years ago
8 0

Answer:

Step-by-step explanation:

That would be 8 x 3. It would help because 24/8 = 3.

Mariulka [41]3 years ago
6 0
If we divide 24 by 8 it gives us the result of 3.

So a multiplication fact is 8x3 = 24.
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Subtract 1.05 from a certain number. Multiply the difference by 0.8, add 2.84 to the product then divide the sum by 0.01 and get
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3 years ago
Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ? f (x) = x3 – 2
butalik [34]

To solve this question, we use the factor theorem, and using it, the polynomial function is:

f(x) = x^3 - 2x^2 - 3x + 6

------------------------------

The factor theorem means that if k is a root of f(x), f(k) = 0.

Thus, applying the factor theorem for this question, we have to choose the function for which: f(2) = 0, f(\sqrt{3}) = 0, f(-\sqrt{3}) = 0

------------------------------

Function 1:

f(x) = x^3 - 2x^2 - 3x + 6

Testing the values:

f(2) = 2^3 - 2(2)^2 - 3(2) + 6 = 8 - 8 - 6 + 6 = 0

f(\sqrt{3}) = \sqrt{3^3} - 2(\sqrt{3})^2 - 3\sqrt{3} + 6 = \sqrt{3^2\times3} - 6 - 3\sqrt{3} + 6 = 3\sqrt{3} - 3\sqrt{3} = 0

f(-\sqrt{3}) = -\sqrt{3^3} - 2(-\sqrt{3})^2 - 3(-\sqrt{3}) + 6 = -\sqrt{3^2\times3} - 6 + 3\sqrt{3} + 6 = -3\sqrt{3} + 3\sqrt{3} = 0

Thus, since all three conditions are satisfied, f(x) = x^3 - 2x^2 - 3x + 6 is the polynomial function.

A similar question is given at brainly.com/question/11378552

5 0
2 years ago
What does f(3)= ? <br> Please help answer me
Zielflug [23.3K]

Answer:

Step-by-step explanation:

6 0
3 years ago
40 points and brainliest answer to the first correct answer:
lilavasa [31]
<span>40.19 + 2.06x


I think its the right one, not sure though

Hope this helped</span>
6 0
3 years ago
Read 2 more answers
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