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2 years ago

What is the correct answer?

Mathematics

1 answer:

emmainna [20.7K]2 years ago

5 0

Answer:

Step-by-step explanation:

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I need some help with math.<br> Who can help me?

Evgesh-ka [11]

Step-by-step explanation:

10^2 = 100

10^-2 = 1/100 ➡ 0.01

5 0

2 years ago

Jennifer earned $1000 babysitting over the summer. She spent $250 of her earnings on new clothes. What percent of her earnings d

emmainna [20.7K]

Answer:

25%

Step-by-step explanation:

she earned $1,000

she spent $250

250/1000 = 0.25

0.25 x 100 = 25%

4 0

2 years ago

Read 2 more answers

Mrs. Olive used 1 2/5 quarts of syrup and 5 3/10 quarts of water to make lemonade. How many quarts of lemonade did she make? * A

Flura [38]

Answer:

B. 6 7/10

Step-by-step explanation:

We solve the above y by carrying out addition.

The quarts of Lemonade she made is calculated as:

1 2/5 quarts of syrup + 5 3/10 quarts of water

= 1 + 5 + (2/5 + 3/10)

Lowest common denominator = 10

= 6 ( 4 + 3/10)

= 6 7/10 quarts of Lemonade

Mrs Olive made 6 7/10 quarts of Lemonade

3 0

3 years ago

Claire traveled 701 miles. She drove 80 miles every day. On the last day of her trip she only drove 61 miles. Write and solve an

mina [271]

Answer:

Claire traveled for 9 days.

Step-by-step explanation:

Given:

Total Distance traveled = 701 miles

Distance traveled each day = 80 miles

Distance traveled on last day = 61 miles

We need to find the number of days Claire traveled.

Solution:

Let the number of days Claire traveled be denoted by 'd'.

Now we can say that;

Total Distance traveled is equal to sum of Distance traveled each day multiplied by number of days and Distance traveled on last day.

framing in equation form we get;

$80d+61=701$

Now Subtracting both side by 61 using Subtraction Property of Equality we get;

$80d+61-61=701-61\\\\80d = 640$

Now Dividing both side by 80 we get;

$\frac{80d}{80}=\frac{640}{80}\\\\d=8$

Hence Claire traveled 80 miles in 8 days and 61 miles on last day making of total <u>9 days</u> of travel.

7 0

3 years ago

Which polynomial correctly combines the like terms and puts the given polynomial in standard form?

Minchanka [31]

Answer: $-5x^3y^3+8x^4y^2-7xy^5+x^2y^4+8x^6$

Step-by-step explanation:

$-5x^3y^3+8x^4y^2-xy^5-2x^2y^4+8x^6+3x^2y^4-6xy^5$

$-5x^3y^3+8x^4y^2+(-xy^5-6xy^5)+(-2x^2y^4+3x^2y^4)+8x^6$

$-5x^3y^3+8x^4y^2+(-7xy^5)+(x^2y^4)+8x^6$

$-5x^3y^3+8x^4y^2-7xy^5+x^2y^4+8x^6$

8 0

3 years ago

Read 2 more answers