The x - intercept of 5x - 3y = 15 is (3, 0)
The y -intercept of 5x - 3y = 15 is (0, -5)
<h3><u>Solution:</u></h3>
Given equation is 5x - 3y = 15
<em><u>To find: x - intercept and y -intercept</u></em>
The x intercept is the point where the line crosses the x axis. At this point y = 0
The y intercept is the point where the line crosses the y axis. At this point x = 0.
<em><u>Finding x - intercept:</u></em>
To find the x intercept using the equation of the line, plug in 0 for the y variable and solve for x
So put y = 0 in given equation
5x - 3(0) = 15
5x = 15
x = 3
So the x - intercept is (3, 0)
<em><u>Finding y - intercept:</u></em>
To find the y intercept using the equation of the line, plug in 0 for the x variable and solve for y
So put x = 0 in given equation
5(0) - 3y = 15
-3y = 15
y = -5
So the y - intercept is (0, -5)
Opposite sides are parallel
Opposite angles are congruent
Opposite sides are congruent.
Answer:

Step-by-step explanation:
As per the problem, the given triangle is a right triangle. This is signified by the box around one of its angles, this box states that the angle it is surrounding is a right angle.
Since it is a right triangle, one can use the Pythagorean theorem to solve this problem. The Pythagorean theorem states that; (
), where (
) and (
) are the legs of the right triangle, or the sides adjacent to the right angle. (
) is the hypotenuse or the side opposite the right angle.
Substitute in the given values and solve, note that (
) represents the unknown leg (side).

Inverse operations,

53=20+x
Subtract 20 from 20 and 53
33=x
Hope this helps!
P.S.
Nice tab theme :P
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S = 
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer