45
Find ten percent of 50 by moving the decimal point left once and subtract it from 50
The numbers are: 36 and 11 .
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Explanation:
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Let us represent the TWO (2) numbers with the variables;
"x" and "y" .
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x + y = 47 .
y − x = 25.
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Since: " y − x = 25 " ;
Solve for "y" in terms of "x" ;
y − x = 25 ;
Add "x" to each side of the equation:
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y − x + x = 25 + x ;
to get:
y = 25 + x .
Now, since:
x + y = 47 ;
Plug in "(25 + x)" as a substitution for "y"; to solve for "x" :
x + (25 + x) = 47 ;
x + 25 + x + 47 ;
2x + 25 = 47 ;
Subtract "25" from each side of the equation:
2x + 25 − 25 = 47 − 25 ;
2x = 22 ;
Divide EACH SIDE of the equation by "2" ;
to isolate "x" on one side of the equation; and to solve for "x" ;
2x / 2 = 22 / 2 ;
x = 11 ;
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x + y = 47<span> ;
</span>Plug in "11" for "x" into the equation ; to solve for "y" ;
11 + y = 47 ;
Subtract "11" from EACH SIDE of the equation;
to isolate "y" on one side of the equation; and to solve for "y" ;
11 + y − 11 = 47 − 11 ;
y = 36 .
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So: x = 11 , y = 36 ;
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Let us check our work:
y − x = 25 ;
36 − 11 =? 25 ? Yes!
x + y = 47 ;
36 + 11 =? 47 ? Yes!
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The numbers are: 36 and 11 .
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Answer:
Option (1)
Step-by-step explanation:
From the picture attached,
Triangle CAB is a right triangle.
Therefore, m∠1 = 90°
Similarly, m∠ACD = 90°
m∠ACD = m∠ACB + m∠BCD = 90°
= m∠3 + m∠4 = 90°
Since m∠4 = 35°,
m∠3 + 35° = 90°
m∠3 = 90° - 35°
= 55°
In the triangle ABC,
m∠ACB + m∠CBA + m∠BAC = 180° [Property of a triangle]
m∠3 + m∠2 + m∠1 = 180°
55° + m∠2 + 90° = 180°
m∠2 + 145° = 180°
m∠2 = 180° - 145°
= 35°
Since, AB║CD and BC is a transverse,
Therefore, m∠2 = m∠4 = 35° [Alternate interior angles]
Option (1) is the correct option.
