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Ivanshal [37]
2 years ago
9

Qual foi o objetivo da implantação da zona franca de manaus ?​

Geography
1 answer:
kherson [118]2 years ago
7 0

Answer:

La zona económica franca de Manaus está ubicada en el estado de Amazonas, en la parte norte de Brasil. Fue fundada el 28 de febrero de 1967, convirtiéndose en la primera zona económica establecida en Brasil, con el objetivo de impulsar el desarrollo económico y social de la región norte, históricamente relegada respecto del resto del país. Habiendo recibido importantes ventajas económicas (beneficios fiscales y comerciales, exención de todos los bienes y componentes importados de los derechos de importación), la zona económica franca se ha convertido en el principal fabricante de computadoras y teléfonos móviles del país.

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Source: www.history.com
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Most countries in Latin America are federal presidential republics. This usually means that
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What happens when silicon atoms bond?
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When silicon atoms bond, then silicates form which are minerals in which such elements as potassium, calcium, magnesium and aluminum combine with the silicon atoms to form minerals like feldspars of different types or if it is just silicon and oxygen that bond then it forms quartz. 
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3 years ago
What is the value of X6? <br><br> Show the solution.
wariber [46]

Answer : The value of x_6 is \sqrt{7}.

Explanation :

As we are given 6 right angled triangle in the given figure.

First we have to calculate the value of x_1.

Using Pythagoras theorem in triangle 1 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_1)^2=(1)^2+(1)^2

x_1=\sqrt{(1)^2+(1)^2}

x_1=\sqrt{2}

Now we have to calculate the value of x_2.

Using Pythagoras theorem in triangle 2 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_2)^2=(1)^2+(X_1)^2

(x_2)^2=(1)^2+(\sqrt{2})^2

x_2=\sqrt{(1)^2+(\sqrt{2})^2}

x_2=\sqrt{3}

Now we have to calculate the value of x_3.

Using Pythagoras theorem in triangle 3 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_3)^2=(1)^2+(X_2)^2

(x_3)^2=(1)^2+(\sqrt{3})^2

x_3=\sqrt{(1)^2+(\sqrt{3})^2}

x_3=\sqrt{4}

Now we have to calculate the value of x_4.

Using Pythagoras theorem in triangle 4 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_4)^2=(1)^2+(X_3)^2

(x_4)^2=(1)^2+(\sqrt{4})^2

x_4=\sqrt{(1)^2+(\sqrt{4})^2}

x_4=\sqrt{5}

Now we have to calculate the value of x_5.

Using Pythagoras theorem in triangle 5 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_5)^2=(1)^2+(X_4)^2

(x_5)^2=(1)^2+(\sqrt{5})^2

x_5=\sqrt{(1)^2+(\sqrt{5})^2}

x_5=\sqrt{6}

Now we have to calculate the value of x_6.

Using Pythagoras theorem in triangle 6 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_6)^2=(1)^2+(X_5)^2

(x_6)^2=(1)^2+(\sqrt{6})^2

x_6=\sqrt{(1)^2+(\sqrt{6})^2}

x_6=\sqrt{7}

Therefore, the value of x_6 is \sqrt{7}.

5 0
2 years ago
Using the rank-size rule, a country's fourth largest city is expected to be about a ________ of the size of the largest city.
Cerrena [4.2K]

Answer:

1/4

Explanation:

According to the rank-size rule the nth largest country is equal to 1/n size of the largest country

8 0
3 years ago
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