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Olin [163]
3 years ago
11

Houa's family took a road trip to the Grand Canyon. Houa fell asleep 29% of the way

Mathematics
1 answer:
gtnhenbr [62]3 years ago
7 0

Answer:

232 miles had travelled when Houa fell asleep.

Step-by-step explanation:

1. .29 x 800 = 232

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Emma bought presents for her mom and her grandmamma for Mother's Day. She bought 1 box of strawberries with 24 strawberries in i
Jobisdone [24]
You simplify 24/12 to receive the answer. The answer must be an improper fraction.
6 0
3 years ago
Write parametric equations of the line with the equation 4x-6y=-12<br><br> HELP FAST
zimovet [89]

Answer: x = t, y = 2t/3 + 2

Step-by-step explanation:

You want to write both x and y in terms of t

so if you rearrange 4x - 6y = -12 you get

-6y = -4x - 12

6y  = 4x + 12

y = 2x/3 + 2

set x = t

and y = 2t/3 + 2

and that's it!

another one you could do is

x = t/2

y = t/3 + 2

or even

x = 3t/2

y = t + 2

i like this one the most because it looks more elegant

4 0
3 years ago
Read 2 more answers
A. A 5in radius ball is in a
abruzzese [7]

Answer:

52.33%

Step-by-step explanation:

Since, all six sides of the box are touching the ball.

So, all the three dimensions of the box are equal.

Hence, it is a cubical box.

Side length of the box (l)

= diameter of the ball

= 2*radius of the ball

= 2*5

= 10 In.

V_{ball} = \frac{4}{3} \pi r^3

V_{ball} = \frac{4}{3} \times 3.14(5)^3

V_{ball} = \frac{4}{3} \times 3.14\times 125

V_{ball} = \frac{1,570}{3}\: In^3

V_{box} =l^3

V_{box} =(10)^3

V_{box} =1000\: In^3

Percentage of the space in the box occupied by the ball

= \frac{V_{ball}}{V_{box} } \times 100

= \frac{\frac{1,570}{3}}{1000} \times 100

= \frac{1570}{3000} \times 100

= \frac{157}{3}

= 52.33\%

5 0
3 years ago
When sales representatives for a pharmaceutical company drive out of town meetings that require an overnight stay, they receive
blsea [12.9K]
X=number of miles

$329=$175+$0.70x
329-175=.70x
154=.70x
154/.70=x
220miles =x
6 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BE%7D%7B%20%5Csqrt%7BR%20%7B%7D%5E%7B2%7D%20%2B%20W%20%7B%7D%5E%7B2%7D%20L%
AleksandrR [38]

Answer:

R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Step-by-step explanation:

Squaring both sides of equation:

     I^2 = (ER)^2/(R^2 + (WL)^2)

<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)

<=>(ER)^2 - (IR)^2 = (IWL)^2

<=> R^2(E^2 - I^2) = (IWL)^2

<=> R^2 = (IWL)^2/(E^2 - I^2)

<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Hope this helps!

7 0
3 years ago
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