we can factor the whole thing:
(2sin(x) -1)(sin(x)+1) = 0.
Therefore, sin(x) = -1 and sin(x) = 1/2.
For the first one x = 3π/2 and the second is π/6 and 5π/6
So 3π/2, π/6 and 5π/6 are the solutions.
I do kind of have a problem with this because it doesn't mention if you should go over 360°. Otherwise, you have to add in an 2nπ into the equations like 3π/2 + 2nπ; 
but I don't know if that is necessary for you.
-36-8 = -44
-36+(-8) = -44
third option
Answer:
D
Step-by-step explanation:
Can I have Brainliest? I hope this helped and have a nice day!!!
Work:
64 / 2 = 32
3/4 / 2 = 3/8
3/4 = 6/8
6/8 / 2 = 3/8
Final answer 32 3/8
Answer:
Step-by-step explanation:
1.
Equation one:
x = -5, x = -1 (Both are real)
Equation two:
No real solutions
Equation three:
x = -3 (Real)
Equation four:
No real solutions
2.
The easiest way to figure out if an equation has real solutions is to factor it. If it is factorable, then it has real solutions. If it isn't, then it doesn't have real solutions.
Answer:
???? did u type it correctly?
