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Alina [70]
3 years ago
12

Please solve this help

Mathematics
1 answer:
JulsSmile [24]3 years ago
8 0

Answer:

the answer is the 3rd option. Hope it helped :)

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Question 5
geniusboy [140]

Answer:

\frac{4}{9}

Step-by-step explanation:

To find this probability, we have to know:

  • How many numbers are there in between 5 and 8 inclusive?
  • How many total numbers are there?

We simply divide the first answer by the second one and get our probability.

So, the numbers are 5,6,7,8 ----- that is 4 numbers

How many numbers are there in total?  That is:

0, 1, 2, 3, 4, 5, 6, 7, 8, or 9  ------- 9 numbers

Thus, the probability is 4/9

7 0
3 years ago
Are these answers right? Questions are below!
Ipatiy [6.2K]

Answer:

8 yes

10 yes

11 yes

12 yes

13 yes

7 0
3 years ago
Read 2 more answers
Help! what is the surface area of the figure?
rjkz [21]

Answer:

220 cm^2

Step-by-step explanation:

3 0
3 years ago
The city has an average of 13 days of rainfall for April.
zhenek [66]

Using the Poisson distribution, we have that:

  • There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.
  • There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.
  • There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

The parameters are:

  • x is the number of successes
  • e = 2.71828 is the Euler number
  • \mu is the mean in the given interval.

For this problem, the mean is given as follows:

\mu = 13

The probability of having exactly 10 days of precipitation in the month of April is P(X = 10), hence:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 10) = \frac{e^{-13}13^{10}}{(10)!} = 0.0859

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

The probability of having less than three days of precipitation in the month of April is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-13}13^{0}}{(0)!} \ approx 0

P(X = 1) = \frac{e^{-13}13^{1}}{(1)!} = 0.00003

P(X = 2) = \frac{e^{-13}13^{2}}{(2)!} = 0.00019

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.00003 + 0.00019 = 0.00022

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

For more than 15 days, the probability is:

P(X > 15) = P(X = 16) + P(X = 17) + ... + P(X = 20)

Applying the formula for each of these values and adding them, we have that P(X > 15) = 0.2364, hence:

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

6 0
2 years ago
A rectangular lawn is twice as long as its breadth and its perimeter is 90 m.
Nina [5.8K]
Answer: length = 30, breadth = 15

length = l
breadth = b

l = 2b

2b + b + 2b + b = 90
6b = 90
b = 15

l = 2b
l = 2(15)
length = 30

b = 15
breadth = 15
7 0
3 years ago
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