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2 years ago

Can someone help me out? Pls it’s urgent!!! ASAP! (Geometry) “Complete the proof”

Mathematics

1 answer:

Nikitich [7]2 years ago

6 0

1) $\overline{WX} \cong \overline{UY}$ , $\angle YXZ \cong \angle XYZ$ (given)

2) $\overline{XY} \perp \overline{XY}$ (reflexive property)

3) $\triangle WXY \cong \triangle UYX$ (SAS)

4) $\overline{WY} \perp\overline{ UX}$ (CPCTC)

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PLEASE HELP ME THIS IS DUE TODAY AND I WILL MARK BRAINLEST.

AVprozaik [17]

Answer:

first graph is a function

Step-by-step explanation:

6 0

2 years ago

What are the intercepts of the equation <br> 2x+3/2y+3z=6

Ne4ueva [31]

X-intercept => 2x = 6 => x = 3
x-intercept is 3.

y-intercept => 3/2y = 6 => y = 4
y-intercept is 4.

z-intercept => 3z = 6 => z = 2
z-intercept is 2.

3 0

2 years ago

Helppp me plsssssssss<br><br>

Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

$\sf \:\:\:\:\:\:\:\:\:\:x_{k}=35$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k}=50$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42$
$\sf \:\:\:\:\:\:\:\:\:\:h=5$

${\bf \:\: {By\:using\:the\: formula}} \\ \\$

$\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\$

$\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\$

${\large{\frak{\pmb{\underline{Additional\: information }}}}}$

MODE

Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

In a frequency distribution the class having maximum frequency is called the modal class.

${\bf{\underline{Formula\:for\: calculating\:mode:}}} \\$

${\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\$

Where,

$\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.$

$\small \blue{ \bigstar}$ $\sf \: f_{k}=frequency\:of\:the\:modal\:class$

$\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class$

$\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class$

$\small \purple{ \bigstar}$ $\sf \: h= width \:of\:the\:class\:interval$

7 0

3 years ago

Lydia wants to find the height of a flagpole. She measures the height of a tree and the length of the shadow it casts. The tree

cricket20 [7]

The hight of the flag pole is i would say 44ft but i am not sure

7 0

3 years ago

True or False

Nady [450]

Answer:

an expression, the exponent indicates how

any times the base is used as a factor. false.

Step-by-step explanation:

beacuse i guess iam smart

3 0

3 years ago