Question

The scores for a particular examination are normally distributed with a mean of 68.5% and a standard deviation of 8.2%. What is the probability that a student who wrote the examination had a mark between 80% and 100%? Give your answer to the nearest hundredth.

Answer 1

Answer:

$P(80/100$

Step-by-step explanation:

We are given that

Mean,$\mu=68.5$%=68.5/100

Standard deviation, $\sigma=8.2$%=8.2/100

We have to find the probability that a student who wrote the examination had a mark between 80% and 100%.

$P(80/100$

$P(80/100$

We know that

$P(a$

Using the formula

$P(80/100$

$P(80/100$

$P(80/100$