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Olin [163]
2 years ago
14

The scores for a particular examination are normally distributed with a mean of 68.5% and a standard deviation of 8.2%. What is

the probability that a student who wrote the examination had a mark between 80% and 100%? Give your answer to the nearest hundredth.
Mathematics
1 answer:
stepladder [879]2 years ago
6 0

Answer:

P(80/100

Step-by-step explanation:

We are given that

Mean,\mu=68.5%=68.5/100

Standard deviation, \sigma=8.2%=8.2/100

We have to find the probability that a student who wrote the examination had a mark between 80% and 100%.

P(80/100

P(80/100

We know that

P(a

Using the formula

P(80/100

P(80/100

P(80/100

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2a + 3b = 5<br> b = a - 5
Lunna [17]
<h2>1st Equation:</h2>

Answer for A:

a =  \frac{5 - 3b}{2}

Answer for B:

b =  \frac{5 - 2b}{3}

<h2>2nd Equation:</h2>

Answer:

a = b + 5

<u>hope it helps</u><u>.</u>

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A is the midpoint of BC. <br> BA = 3x+8 <br> AC=23. <br> solve for x
AnnyKZ [126]

Since A is the midpoint of BC, we can assume BA and AC are equal to each other.

We also know that BC = BA + AC = 23 + 23 = 46

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What is the approximate area of the shaded sector in the circle shown below?
BabaBlast [244]

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Given the function f(x)=6x-11, find f(-1/3).
Nadya [2.5K]

Answer:

-13

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7 0
2 years ago
Solve for x.
egoroff_w [7]

∑ Hey, KLPJDP615 ⊃

Answer:

x = 6 or x = -10

Step-by-step explanation:

<u><em>Given:</em></u>

<em>Solve for x.</em>

<em>1 + |2+x|= 9</em>

<em>O x = 4 or x = -8</em>

<em>O x = 7 or X = -11</em>

<em>O x = 5 or x = -9</em>

<em>x = 6 or X = -10 </em>

<u><em>Solve:</em></u>

<em>1 + |2+x|= 9</em>

<em>Subtract 1 from both sides:</em>

<em>1 + |2 +x| -1 = 9-1 </em>

<em>Simplify</em>

<em>|2 + x | = 8</em>

<em>Applying absolute value rule:  If |u| = a, a > 0 then u = a or u = -a</em>

<em>2 + x = -8</em>

<em>2 + x = 8</em>

<u><em>Solving:</em></u>

<em>2 + x = -8</em>

<em>2 - 2 + x = -8 - 2</em>

<em>x = -10</em>

<u><em>Solving:</em></u>

<em>2 + x = 8</em>

<em>2 - 2 + x = 8 - 2</em>

<em>x = 6</em>

<em />

<em>Hence, x = 6 or x = -10</em>

<em />

<u><em>xcookiex12</em></u>

<em>8/26/2022</em>

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1 year ago
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