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Olin [163]
3 years ago
14

The scores for a particular examination are normally distributed with a mean of 68.5% and a standard deviation of 8.2%. What is

the probability that a student who wrote the examination had a mark between 80% and 100%? Give your answer to the nearest hundredth.
Mathematics
1 answer:
stepladder [879]3 years ago
6 0

Answer:

P(80/100

Step-by-step explanation:

We are given that

Mean,\mu=68.5%=68.5/100

Standard deviation, \sigma=8.2%=8.2/100

We have to find the probability that a student who wrote the examination had a mark between 80% and 100%.

P(80/100

P(80/100

We know that

P(a

Using the formula

P(80/100

P(80/100

P(80/100

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Answer:

Domain = -2, range = -5

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domain = 2, range = 5

let y =>f(x)

It can be seen that Function can be linear having common difference 2

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let's check

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