For every value tht x increases, y decreases by 3
-3x
Then to find the y intercept, look at 0's corresponding value (8)
-3x+8
Answer:
0.281 = 28.1% probability a given player averaged less than 190.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
A bowling leagues mean score is 197 with a standard deviation of 12.
This means that ![\mu = 197, \sigma = 12](https://tex.z-dn.net/?f=%5Cmu%20%3D%20197%2C%20%5Csigma%20%3D%2012)
What is the probability a given player averaged less than 190?
This is the p-value of Z when X = 190.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{190 - 197}{12}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B190%20-%20197%7D%7B12%7D)
![Z = -0.58](https://tex.z-dn.net/?f=Z%20%3D%20-0.58)
has a p-value of 0.281.
0.281 = 28.1% probability a given player averaged less than 190.
Answer:
The length of the actual train's car is <u>67.5 feet.</u>
Step-by-step explanation:
Given:
The scale of a model train is 1 inch to 13.5 ft.
Now, to get the length of the actual car of the train.
Let the length of actual train's car be ![x.](https://tex.z-dn.net/?f=x.)
And, the length of the car of model train = ![5\ inches\ long.](https://tex.z-dn.net/?f=5%5C%20inches%5C%20long.)
<em>According to the scale of the model train, 1 inch is equivalent to 13.5 ft. </em>
<em>Thus, 5 inches is equivalent to </em>
<em />
Now, to get the length of actual train's car using cross multiplication method:
![\frac{1}{13.5} =\frac{5}{x}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B13.5%7D%20%3D%5Cfrac%7B5%7D%7Bx%7D)
By cross multiplying we get:
![x=67.5\ feet.](https://tex.z-dn.net/?f=x%3D67.5%5C%20feet.)
Therefore, the length of the actual train's car is 67.5 feet.
Answer:
$800
Step-by-step explanation:
![total \: units \: = \\ 2 + 3 + 4 = 9 \: units \\ 9 \: units \: = 1800 \\ 1 \: unit \: = 1800 \div 9 \: = 200 \\ largest \: share \: = 4 \: units \\ 4 \: units \: = \: 200 \times 4 = 800](https://tex.z-dn.net/?f=total%20%5C%3A%20units%20%5C%3A%20%20%3D%20%20%5C%5C%202%20%2B%203%20%2B%204%20%3D%209%20%5C%3A%20units%20%5C%5C%209%20%5C%3A%20units%20%5C%3A%20%20%3D%201800%20%5C%5C%201%20%5C%3A%20unit%20%5C%3A%20%20%3D%201800%20%5Cdiv%209%20%5C%3A%20%20%3D%20200%20%5C%5C%20largest%20%5C%3A%20share%20%5C%3A%20%20%3D%204%20%5C%3A%20units%20%5C%5C%204%20%5C%3A%20units%20%5C%3A%20%20%3D%20%20%5C%3A%20200%20%5Ctimes%204%20%3D%20800)