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ser-zykov [4K]
2 years ago
13

Please Help Me i will do anything

Mathematics
1 answer:
CaHeK987 [17]2 years ago
5 0

A=4n

B=4n+-9

C=9n-4n

D=(n-36)4

E=4(n-9

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Write the equation of the line that passes through the points (-4,8) and (-2, -1).
IRINA_888 [86]

Answer:

y=-9/2x-10

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-1-8)/(-2-(-4))

m=-9/(-2+4)

m=-9/2

y-y1=m(x-x1)

y-8=-9/2(x-(-4))

y-8=-9/2(x+4)

y=-9/2x-36/2+8

y=-9/2x-18+8

y=-9/2x-10

5 0
2 years ago
Find the directional derivative of the function at the given point in the direction of the vector v. F(x, y, z) = xey + yez + ze
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3 years ago
The histogram below displays the distribution of 50 ages at death due to trauma (unnatural accidents and homicides) that were ob
sattari [20]

Answer:

d. The median and the IQR

Step-by-step explanation:

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The first quartile(Q1) separates the lower 25% from the upper 75% of a set. So 25% of the values in a data set lie at or below the first quartile, and 75% of the values in a data set lie at or above the first quartile.

The third quartile(Q3) separates the lower 75% from the upper 25% of a set. So 75% of the values in a data set lie at or below the third quartile, and 25% of the values in a data set lie at or the third quartile.

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So the correct answer is:

d. The median and the IQR

5 0
3 years ago
A principal of $2000 is placed in a savings account at 3% per annum compounded annually. How much is in the account after one ye
natita [175]

Answer:

Step-by-step explanation:

After one year

A=p(1+r/n)^nt

=2000(1+0.03/12)^12*1

=2000(1+0.0025)^12

=2000(1.0025)^12

=2000(1.0304)

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After two-years

A=p(1+r/n)^nt

=2060.8(1+0.03/12)^12*2

=2060.8(1+0.0025)^24

=2060.8(1.0025)^24

=2060.8(1.0618)

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After three years

A=p(1+r/n)^nt

=2188.157(1+0.03/12)^12*3

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=2188.157(1.0025)^36

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8 0
3 years ago
What is 20-5+80(78)-10? Please help, I am not good at algebra!
rodikova [14]
The answer to your question is   6245 <span> </span>
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3 years ago
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