Answer: 123
Step-by-step explanation:
9514 1404 393
Answer:
- (c1, c2, c3) = (-2t, 4t, t) . . . . for any value of t
- NOT linearly independent
Step-by-step explanation:
We want ...
c1·f1(x) +c2·f2(x) +c3·f3(x) = g(x) ≡ 0
Substituting for the fn function values, we have ...
c1·x +c2·x² +c3·(2x -4x²) ≡ 0
This resolves to two equations:
x(c1 +2c3) = 0
x²(c2 -4c3) = 0
These have an infinite set of solutions:
c1 = -2c3
c2 = 4c3
Then for any parameter t, including the "trivial" t=0, ...
(c1, c2, c3) = (-2t, 4t, t)
__
f1, f2, f3 are NOT linearly independent. (If they were, there would be only one solution making g(x) ≡ 0.)
Answer:
62.83
because you take 20, divide it by 2 to get the radius then you have the equation 2π(10)
Answer:
10
Explanation:
1
0
− 6
0 + 2
1 = 2
+ 4
1
1
0
− 3
9 = 2
+ 4
1
1
0
− 3
9 + 3
9 = 2
+ 4
1 + 3
9
x = 10
Answer: 20d + 5
Step-by-step explanation:
First we need to combine like terms.
In this equation we can see that they're are 3 numbers containing the letter D we have -4, -4, 28.
We're going to combine -4 and -4 to get -8 and then combine -8 to 28 getting 20d
Afterwards we're going to combine 3, 2 equaling 5.
