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Anna11 [10]
3 years ago
14

Please I need help I wasn’t at school today

Mathematics
1 answer:
Viktor [21]3 years ago
7 0
The slope would be 3/2.
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Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(
Stells [14]

Answer:

f(x) =  {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x  \rightarrow \: x = sec \: y\\  \frac{dx}{dx}  =  \frac{d(sec \: y)}{dx}  \\ 1 = \frac{d(sec \: y)}{dx} \times  \frac{dy}{dy}  \\ 1 = \frac{d(sec \: y)}{dy} \times  \frac{dy}{dx}  \\1 = tan \: y.sec \: y. \frac{dy}{dx}  \\ \frac{dy}{dx} =  \frac{1}{tan \: y.sec \: y}  \\ \frac{dy}{dx} =  \frac{1}{ \sqrt{( {sec}^{2}   \: y - 1}) .sec \: y}  \\ \frac{dy}{dx} =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} } \\   \therefore  \frac{d( {sec}^{ - 1}x) }{dx}  =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx}  =  \frac{1}{ |5x |  \sqrt{25 {x }^{2}  - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx}  =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} }

4 0
2 years ago
ANSWER BOTH!!! A. An international company has 18,600 employees in one country. If this represents 18.2% of the company's employ
bulgar [2K]

Answer:

A. 102,198 employees

B. $22,120 decrease

$293,880 current value

Step-by-step explanation:

6 0
3 years ago
Help..................
Salsk061 [2.6K]

Answer:

Yes

Step-by-step explanation:

It has a 45 degree angle

5 0
3 years ago
Read 2 more answers
1. You roll a standard number cube. Find P(number greater than 2).
ra1l [238]

Answer:

P={3,4,5,6}

Step-by-step explanation:

Cube=6 sides={1,2,3,4,5,6}

P>2

P={3,4,5,6}

7 0
3 years ago
X-42=-33 what is the solution ?
bogdanovich [222]
X = -33 + 42
x = 42 - 33
x = 9
5 0
3 years ago
Read 2 more answers
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