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Kamila [148]
3 years ago
8

A local zoo has two large snakes. The anaconda is currently 5.23 meters long and grows 1.27 meters every month. The python is 4.

76 meters long and grows 2.04 meters per month. How many months ( ) m does the zookeeper need to wait for the two snakes to be the same length? a. Write the question or problem statement for the situation. _______________________________________________________________________________ _______________________________________________________________________________ b. Write the general form of the equation. _______________________________________________________________________________ c. Write the verbal and variable expression for the left side of the equation. _______________________________________________________________________________ d. Write the verbal and variable expression for the right side of the equation. _______________________________________________________________________________ e. Write the final algebraic equation with variables on both sides. Include what the variable represents in the problem. Include appropriate units. ____________________________________________________________
Mathematics
1 answer:
kari74 [83]3 years ago
6 0

Answer:

see below

Step-by-step explanation:

a.  We want to see when the two snakes will be the same length.

b.   b1 + r1m= b2 + r2m  where b is the initial length and m is the number of months and r is the  growth rate

c.   for the anaconda  5.23 + 1.27 m  where m is the number of months,  and the total length is in meters

The anaconda starts at 5.23 meters and grows 1.27 meters each month for m months

d.  for the python 4.76 + 2.04m   where m is the number of months, l is the length of the python in meters

The python starts at 4.76 meters and grows 2.04 meters each month for m months

e.  5.23 + 1.27 m  = 4.76 + 2.04m   m is the number of months  Each side is the number of meters

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In an upcoming race, the top 3 finishers will be recognized with the same award. There are 12 people entered in the race.
slavikrds [6]

Answer:

220

Step-by-step explanation:

Given,

The total number of people = 12,

Out of which, top 3 finishers will be recognized with the same award,

So, the total possible way = total combination of 3 people out of 12 people

=^{12}C_3

=\frac{12!}{3!(12-3)!}

=\frac{12\times 11\times 10\times 9!}{3\times 2\times 9!}

=\frac{1320}{6}

=220

Hence, there are 220 ways the top 3 racers can be grouped from the 12 people.

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3 years ago
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Goryan [66]

2 - 3i is just another of writing (2, -3) in the cartesian plane, the 2-3i however is using the "imaginary axis" for the imaginary plane, is all however the imaginary axis is simply the equivalent of the y-axis.  Likewise 9+21i is just (9,21), so let's just use the distance formula.

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Ne4ueva [31]
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Dovator [93]

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Let's start by subtracting 3 from both sides

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