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Firdavs [7]
3 years ago
6

Which unit would be most suitable for its scale?

Physics
1 answer:
Cloud [144]3 years ago
5 0

Answer:

Mm, thats the answer trust me men

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A particle moves in a velocity field V(x, y) = x2, x + y2 . If it is at position (x, y) = (7, 2) at time t = 3, estimate its loc
MArishka [77]

Answer:

New location at time 3.01 is given by: (7.49, 2.11)

Explanation:

Let's start by understanding what is the particle's velocity (in component form) in that velocity field at time 3:

V_x=x^2=7^2=49\\V_y=x+y^2=7+2^2=11

With such velocities in the x direction and in the y-direction respectively, we can find the displacement in x and y at a time 0.01 units later by using the formula:

distance=v\,*\, t

distance_x=49\,(0.01)=0.49\\distance_y=11\,(0.01)=0.11

Therefore, adding these displacements in component form to the original particle's position, we get:

New position: (7 + 0.49, 2 + 0.11) = (7.49, 2.11)

6 0
3 years ago
the face of a cube towards A is brightly and shiny and the face towards V is full black.State with reason the adjustments that s
MariettaO [177]

Explanation:

increase the distance of cube from black and dull substance

5 0
3 years ago
To understand the decibel scale. The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the d
inna [77]

Answer:

10 db

Explanation:

Detailed explanation and calculation is shown in the image below

6 0
3 years ago
When the atmosphere is absolutely unstable, the environmental lapse rate is ________ the dry adiabatic lapse rate.
insens350 [35]

Answer: greater than

Explanation:

5 0
3 years ago
A horizontal force of 750 N is needed to overcome the force of static friction between a level floor and a 250-kg crate. What is
loris [4]

Answer:

The acceleration of the crate is 1.82\ m/s^2.

Explanation:

Given that,

Force, F = 750 N

Mass of the crate, m = 250 kg

The coefficient of friction is 0.12.

We need to find the acceleration of the crate. The net force acting on the crate is given by :

F=ma\\\\F-f=ma

f is frictional force, f=\mu N=\mu mg

F-\mu mg=ma\\\\a=\dfrac{F-\mu mg}{m}\\\\a=\dfrac{750-0.12\times 250\times 9.8}{250}\\\\a=1.82\ m/s^2

So, the acceleration of the crate is 1.82\ m/s^2. Hence, this is the required solution.

4 0
3 years ago
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