This question involves the concepts of dynamic pressure, volume flow rate, and flow speed.
It will take "5.1 hours" to fill the pool.
First, we will use the formula for the dynamic pressure to find out the flow speed of water:
where,
v = flow speed = ?
P = Dynamic Pressure = 55 psi
= 379212 Pa
= density of water = 1000 kg/m³
Therefore,
v = 27.54 m/s
Now, we will use the formula for volume flow rate of water coming from the hose to find out the time taken by the pool to be filled:
where,
t = time to fill the pool = ?
A = Area of the mouth of hose = 
= 1.98 x 10⁻⁴ m²
V = Volume of the pool = (Area of pool)(depth of pool) = A(1.524 m)
V = ![[\frac{\pi (9.144\ m)^2}{4}][1.524\ m]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%5Cpi%20%289.144%5C%20m%29%5E2%7D%7B4%7D%5D%5B1.524%5C%20m%5D)
= 100.1 m³
Therefore,
<u>t = 18353.5 s = 305.9 min = 5.1 hours</u>
Learn more about dynamic pressure here:
brainly.com/question/13155610?referrer=searchResults
The change in energy after the collision is <u>0.5</u>
<u />
<h3>What is change in energy?</h3>
This refers to the difference in the energy where energy is the capacity to do work. There different forms of energy they include mechanical energy, solar energy, electrical energy and so on.
The energy described in the problem is mechanical energy and it is of two types kinetic energy and potential energy
<h3>solving for the change in energy as a result of the collision</h3>
where mass of particle mp = 4 kg
mass of object mb = 6 kg
force constant of spring k = 100 N/m
amplitude A = 2 m
kinetic energy = 1/2 mv^2
initial velocity u = Aω
ω = sqrt ( 100/ 4 )
u = 2 sqrt ( 100/ 4 )
u = 10m/s
final velocity v = 5 m/s
change in energy
= - 0.5 * ( 4 + 4 ) * 5^2 + 0.5 * 4 * 10^2 ) / 0.5 * 4 * 10^2
= 0.5
Read more on change in energy here: brainly.com/question/26066414
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Answer:
The equipment to use is: a beaker, a fixed amount of water, a thermometer.
The mass of water, the time, the temperature for each time should be noted and a graph of Temperature versus time should be made
Explanation:
The design of an experiment is to place the beaker in the microwave, with a good amount of water (approximately ⅔ of its capacity) and turn it on for small periods of time, generally the minimum is 30 s, quickly open the microwave, place a thermometer or better yet an infrared thermometer to measure the temperature of the water; repeat this several times.
The advantage of the infrared thermometer is that it reduces the transfer of heat between the water and the thermometer.
The mass of water, the time, the temperature for each time should be noted and a graph of Temperature versus time should be made.
The equipment to use is: a beaker, a fixed amount of water, a thermometer.
The main precaution that must be taken is not to open the microwave while it is on.
Answer: Heat is removed from the room at 12W
Explanation: Since the room is insulated, no heat can leave the room except it is air conditioned.
The engine does work at a rate ∆W/t = 450W
Power is generated at a rate ∆Q/t = 438W
Net change in energy = (∆Q-∆W)/t
= ∆Q/t - ∆W/t
= (438 - 450)W
= 12W
