Quadratic equations w complex roots x2 - 6x + 12 = 0
1 answer:
Answer:
x = 3 ± i
Step-by-step explanation:
Given
x² - 6x + 12 = 0 ( subtract 12 from both sides )
x² - 6x = - 12
Using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 3)x + 9 = - 12 + 9
(x - 3)² = - 3 ( take the square root of both sides )
x - 3 = ± = ± i
( add 3 to both sides )
x = 3 ± i
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For each <em>x</em> in the interval 0 ≤ <em>x</em> ≤ 5, the shell at that point has
• radius = 5 - <em>x</em>, which is the distance from <em>x</em> to <em>x</em> = 5
• height = <em>x</em> ² + 2
• thickness = d<em>x</em>
and hence contributes a volume of 2<em>π</em> (5 - <em>x</em>) (<em>x</em> ² + 2) d<em>x</em>.
Taking infinitely many of these shells and summing their volumes (i.e. integrating) gives the volume of the region:
