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Zinaida [17]
2 years ago
6

What is the solution to the system of equations graphed below?

Mathematics
1 answer:
sweet [91]2 years ago
5 0

Answer:

\text{B. }(2, -3)

Step-by-step explanation:

\begin{cases}y=2x-7,\\y=-x-1\end

Since y=y:

2x-7=-x-1,\\3x=6,\\x=2

Solving for y:

y=2(2)-7=4-7=-3

Verify that the point of intersection occurs at \boxed{(2, -3)}\checkmark

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olga2289 [7]

Answer:

Yes, buddy ut's 1 your correct x

6 0
2 years ago
Y varies directly with x, and y = 5 when x = 4. What is the value of x when y = 8?
Tomtit [17]
As y varies directly with x, there is a proportionality constant. As x increases by that certain constant, y also increases. We equate:
y = kx
where k = proportionality constant.
Given the condition, y = 5 when x = 4, then we solve for k:
5 = k(4)
k = 5/4 or 1.25
When y = 8, then
8 = (5/4)(x)
x = 8/(5/4) = (8)(4/5) = 32/5 or 6.4 (ANSWER)
7 0
3 years ago
Under the translation T(2, -3) the point (1, 6) will become (3, 9).
seraphim [82]

Answer:

False (under assumption T(2,-3) means move it right 2 units and down 3 units).

Step-by-step explanation:

The statement is false.

T(2,-3) means move the point right 2 (so plus 2 on the x-coordinate) and down 3 units (so minus 3 on the y-coordinate).

So (1,6) will become (1+2,6-3)=(3,3) after the translation.

The point (1,12) will become (1+2,12-3)=(3,9).

If the statement were "Under the translation T(2,-3) the point (1,12) will become (3,9)", then it would be true.

Or!

If the statement were "Under the translation T(2,3) the point (1,6) will become (3,9)", then it would be true.

3 0
3 years ago
A 16 inch candle is lit and burns at a constant rate of 1.1 inches per hour. Let t represent the never of hours that have elapse
Alex17521 [72]

Answer:

(a) Number of inches that have burned from the candle since it was lit is (1.1t) inches

(b) The remaining length of the candle is (16 - 1.1t) inches

Step-by-step explanation:

(a). Length of candle before it was lit = 16 inches

Constant rate at which at which candle burns = 1.1 inches per hour

Let t represent the number of hours that have elapsed since the candle was lit

In 1 hour, 1.1 inches of the candle burned

Therefore, in t hours, (1.1t) inches of the candle would have burned since the candle was lit

(b) Remaining length of candle = length of candle before it was lit - length of candle that have burned = 16 inches - 1.1t inches = (16 - 1.1t) inches

6 0
3 years ago
Can you solve the 3 questions below?
trasher [3.6K]

Answer:

a - car

b - plane b

10 overs

6 0
2 years ago
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