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3 years ago

One triangle on a graph has a vertical side of 7 and a horizontal side of 12.

1 answer:

4 0

If you are working out the diagonal line you need to use Pythagoras Theroum: c² = a²+b²

c² = 7²+12² = 193
√c² = c = √193 = 13.89

The length of the diagonal side is 13.89,
Hope this helps! :)

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Please help me thank you I appreciate it

Volgvan

Answer:

68°

Step-by-step explanation:

PRQ = SRQ gives:

3x-8 = 2x+6

x = 6+8 = 14

So PRQ = SRQ = 34

and

PRS = PRQ+SRQ = 68

4 0

2 years ago

the diameter of a cylinder is 14cm.the height of the cylinder is 9cm. calculate the Volume and curved surface area

kicyunya [14]

Answer:

The volume is 1386 cm³ and curved surface area is 396 cm².

Step-by-step explanation:

Given that,

The diameter of a cylinder is 14 cm

Height of the cylinder is 9 cm

We need to find the volume and curved surface area .

If r is the radius, r = 14/2 = 7 cm

Volume of a cylinder is given by :

$V=\pi r^2 h\\\\V=\dfrac{22}{7}\times (7)^2 \times 9\\\\V=1386\ \text{cm}^3$

The curved surface area of the cylinder is given by :

$A=2\pi r h\\\\A=2\times \dfrac{22}{7}\times 7\times 9\\\\A=396\ \text{cm}^2$

So, the volume is 1386 cm³ and curved surface area is 396 cm².

3 0

3 years ago

Plsssssss help<br>got 20 mins<br>the question is: The sin of angle DCB is

Elena L [17]

Answer:

i. <DCB = $53.13^{o}$

ii. Sin of <DCB = 0.8

Step-by-step explanation:

Let <DCB be represented by θ, so that;

Sin θ = $\frac{opposite}{hypotenuse}$

Thus from the given diagram, we have;

Sin θ = $\frac{4}{5}$

= 0.8

This implies that,

θ = $Sin^{-1}$ 0.8

= 53.1301

θ = $53.13^{o}$

Therefore, <DCB = $53.13^{o}$ .

So that,

Sin of <DCB = Sin $53.13^{o}$

= 0.8

Sin of <DCB = 0.8

5 0

3 years ago

Anastaziya [24]

Shut up you try hard advertiser. Get deleted

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3 years ago

web based software company is interested in estimating the proportion of individuals who use the Firefox browser. In a sample of

nata0808 [166]

<h2>Answer with explanation:</h2>

Let $\hat{p}$ denotes the sample proportion.

As per given , we have

n= 200

$\hat{p}=\dfrac{30}{200}=0.15$

Critical value for 99% confidence : $z_{\alpha/2}=2.576$

Confidence interval for population proportion :-

$\hat{p}\pm z_{\alpha/2} \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.15\pm (2.576)(\sqrt{\dfrac{0.15(1-0.15)}{200}})\\\\\approx0.15\pm0.065\\\\=(0.15-0.065,\ 0.15+0.065)\\\\=(0.085,\ 0.215)$

Hence, a 99% confidence interval for the proportion of all individuals that use Firefox: $(0.085,\ 0.215)$

The lower limit on the 99% confidence interval = 0.085

6 0

3 years ago