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laiz [17]
3 years ago
11

L.C.M of x2 + 3x + 2 and x2 + 4x + 3

Mathematics
2 answers:
Tpy6a [65]3 years ago
8 0

Step-by-step explanation:

1st expression

x2 + 3x + 2

x²+2x+x+2

x(x+2)+1(x+2)

(x+2)(x+1)

2nd expression

x2 + 4x + 3

x²+3x+x+3

x(x+3)+1(x+3)

(x+3)(x+1)

L.C.M=(x+1)(x+2)(x+3)

lutik1710 [3]3 years ago
4 0

Answer:

Step-by-step explanation:

x^2 + 3x + 2 = (x+1)(x+2)

x^2 + 4x + 3 = (x+1)(x+3)

LCM = (x+1)(x+2)(x+3) = (x^2 + 3x + 2) (x+3) = x^3 + 6x^2 + 11x + 6

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3 years ago
Solve for 'p'
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Since these two expressions are equal, and the bases are the same, you know the exponents must be equal, with the exponent on the right hand side being 1. So 2p=1, or p=\dfrac12.
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