Step-by-step explanation:
1st expression
x2 + 3x + 2
x²+2x+x+2
x(x+2)+1(x+2)
(x+2)(x+1)
2nd expression
x2 + 4x + 3
x²+3x+x+3
x(x+3)+1(x+3)
(x+3)(x+1)
L.C.M=(x+1)(x+2)(x+3)
Answer:
x^2 + 3x + 2 = (x+1)(x+2)
x^2 + 4x + 3 = (x+1)(x+3)
LCM = (x+1)(x+2)(x+3) = (x^2 + 3x + 2) (x+3) = x^3 + 6x^2 + 11x + 6
33
4,14,24,34,40,41,42,43,44,45,46,47,48,49,54,64,74,84,94,
104,114,124,134,140,141,142,143,144,145,146,147,148,149
- 2 - 3i
given a complex number a + bi
then the conjugate is a - bi
The real part a remains unchanged while the sign of the imaginary part is reversed.
the conjugate of - 2 + 3i is - 2 - 3i
43,300
Starting with 2 since its in the hundredths and going over one place to the tenths, we see 7 <em>is </em> greater than 5 so we make the 2 a 3 and replace everything after with 0's
43,300!!
