All categories

3 years ago

.

Mathematics

1 answer:

Sedbober [7]3 years ago

7 0

Answer:

point, P and Q Brocard's points. Prove that P and Q belong to the circle with diameter ... 0 < αi < 2π. ... 5. Square P QRS is inscribed into △ ABC so that vertices P and Q lie on sides AB and

You might be interested in

6/12 mas 2/3 mas 1/6

kozerog [31]

Reduce the fraction 6/12 to its lowest expression by extracting and canceling 6.

$\bf{ \dfrac{1}{2}+\dfrac{2}{3}+\dfrac{1}{6} }$

Convert 1/2 and 2/3 to fractions with denominator 6.

$\bf{\dfrac{1\times3}{2\times3}+\dfrac{2\times2}{3\times2}+\dfrac{1}{6} \ \ \to \ \ \ Multiply }$

$\bf{ \dfrac{3}{6}+\dfrac{4}{6}+\dfrac{1}{6} }$

Since 3/6, 4/6, and 1/6 have the same denominator, add their numerators to add them together.

$\bf{\dfrac{3+4+1}{6} \ \ \to \ \ \ Add }$

Add 3 plus 4 plus 1.

$\bf{\dfrac{8}{6} }$

Reduce the fraction 6/8 to its lowest expression by extracting and canceling 2.

$\bf{\dfrac{4}{3} \ \ \to \ \ \ Answer }$

$\red{\boxed{\green{\boxed{\boldsymbol{\sf{\purple{Pisces04}}}}}}}$

3 0

2 years ago

Use the Law of Cosines to find the missing angle. In triangle JKL, j=3in., k=4in., and l=2.89., find mJ

slega [8]

Using the law of cosine for Triangle KJL, we can write:

$j^{2} = k^{2} + l^{2}-2(k)(l)cos(J) \\ \\ 
2(k)(l)cos(J)=k^{2} + l^{2}- j^{2} \\ \\ 
cos(J)= \frac{k^{2} + l^{2}- j^{2}}{2(k)(l)}$

Using the values of k,j and l, we can write:

$cos(J)= \frac{ 4^{2} + (2.89)^{2} - 3^{2} }{2(4)(2.89)} \\ \\ 
cos(J)= 0.664 \\ \\ 
J= cos^{-1}(0.664) \\ \\ 
J=48.39$

Rounding to nearest integer, the measure of angle J will be 48 degrees.
So option B gives the correct answer

8 0

3 years ago

Read 2 more answers

Please help quick, will give brainliest(pic included) thanks :)

Scrat [10]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A company is producing a new product. Due to the nature of the product, the time required to produce each unit decreases as wor

balu736 [363]

Answer:

The total time to produce units 1 through 10 = 21.762 hours

The total time to produce units 30 through 40 = 22.187 hours

Step-by-step explanation:

Function for the learning process is T(x) = 2 + 0.6(1/x)

Time required to produce 1st unit = 2.6

Time required to produce 2nd unit = 2.3

Time required to produce 3rd unit = 2.2

Time required to produce 4th unit = 2.15

Time required to produce 5th unit = 2.12

Time required to produce 6th unit = 2.1

Time required to produce 7th unit = 2.09

Time required to produce 8th unit = 2.075

Time required to produce 9th unit = 2. 067

Time required to produce 10th unit = 2. 06

The total time required for a new worker to produce units 1 through 10 is the sum of the above times. The total time to produce units 1 through 10 = 21.762

Function for the learning process is T(x) = 2 + 0.6(1/x)

Time required to produce 30th unit = 2.02

Time required to produce 31st unit = 2.019

Time required to produce 32nd unit = 2.0188

Time required to produce 33rd unit = 2.018

Time required to produce 34th unit = 2.0176

Time required to produce 35th unit = 2.017

Time required to produce 36th unit = 2.0167

Time required to produce 37th unit = 2.016

Time required to produce 38th unit = 2.0158

Time required to produce 39th unit = 2. 0154

Time required to produce 40th unit = 2. 015

The total time required for a new worker to produce units 30 through 40 is the sum of the above times. The total time to produce units 30 through 40 = 22.187

7 0

3 years ago

A painter can paint 350 square feet in 1.25 hours what is the painting rate per square feet per hour

pashok25 [27]

Answer:280 square feet per hour.

Step-by-step explanation:

7 0

4 years ago